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siniylev [52]
3 years ago
10

Which of the following is not a symptom associated with hypertension

Physics
1 answer:
Romashka-Z-Leto [24]3 years ago
3 0
Do you have any answer choices?

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I have a hot air balloon that has 18.0 g helium gas inside of it. if the pressure is 2.00 atm and the temperature is 297k, what
Anastaziya [24]

M = molar mass of the helium gas = 4.0 g/mol

m = mass of the gas given = 18.0 g

n = number of moles of the gas

number of moles of the gas is given as

n = m/M

n = 18.0/4.0

n = 4.5 moles

P = pressure = 2.00 atm = 2.00 x 101325 Pa = 202650 Pa

V = Volume of balloon = ?

T = temperature = 297 K

R = universal gas constant = 8.314

Using the ideal gas equation

P V = n R T

(202650) V = (4.5) (8.314) (297)

V = 0.055 m³

4 0
3 years ago
Read 2 more answers
Um carro percorre um trecho de 450 km em escalar media do carro
Aleks04 [339]

Average speed of the car is defined as the ratio of total distance and total time

So here we will have

v_{avg} = \frac{distance}{time}

now we know that

distance = 450 km

time = 5 h

now from above equation we will have

v = \frac{450 km}{5 h} = 90 km/h

so the average speed will be 90 km/h

7 0
3 years ago
Four point charges each having charge Q are located at the corners of a square having sides of length a.
Murljashka [212]

Answer:

Explanation:

Given

Four Point charges are Placed at the corner of a square with side length a

Length of diagonal a\sqrt{2}

Distance of charge from center \frac{a\sqrt{2}}{2}=\frac{a}{\sqrt{2}}

Potential at the center due to four charges is given by

V=\frac{4\cdot k\cdot Q}{\frac{a}{\sqrt{2}}}

as all the four charges are equal and placed symmetrical about center

Work done required to bring a fifth charge q from infinity to the center of the square

W=qV

W=\frac{4\sqrt{2}kQq}{a}    

7 0
3 years ago
The total number of protons plus neutrons in an atom of ⁴⁵₂₀Ca is
lys-0071 [83]

Answer:

b

Explanation:easy

6 0
3 years ago
Two objects of unequal mass are connected by a massless cord passing over a frictionless pulley. After the objects are released
Tom [10]

Answer:

a) ∆U < 0 and ∆K > 0

Explanation:

The initial kinetic energy is zero since the objects are at rest

KE₁ = 0

The final kinetic energy is positive which means

KE₂ > 0

Therefore, the change is kinetic energy is positive

∆KE > 0

The change in gravitational potential energy is negative since the masses are unequal

Lets suppose mass of 1st object is m₁ and mass of 2nd m₂ and  m₂ > m₁

∆U = m₁gh (positive)

∆U = m₂gh (negative)

Since m₂ > m₁ Total change in gravitational potential energy will be negative

∆U < 0

Therefore, the correct option is (a)

∆U < 0 and ∆K > 0

7 0
3 years ago
Read 2 more answers
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