All categories

3 years ago

What is the mass of an element with 15 protons, 13 electrons, and 11 neutrons? *

Chemistry

1 answer:

RSB [31]3 years ago

6 0

Answer:

The mass of the element is 26.20 amu

Explanation:

In this question, we are asked to calculate the mass of an element with 15 protons, 13 electrons and 11 neutrons

To calculate the atomic mass of the element, we take into consideration the masses of the individual sub atomic particles

Electrons have 0 atomic mass unit(their masses are negligible) we have no business here, Protons have a mass of

1.00727647 amu, while the mass of neutron is 1.0086654 amu

The mass of 15 protons is thus 15 * 1.00727647 = 15.10914705 amu

The mass of 11 neutrons is 11 * 1.0086654 =

11.0953194 amu

Adding this together, we have ; 11.0953194 + 15.10914705 = approximately 26.20 amu

You might be interested in

GIVE ME BRAINLIEST!!!! nah im jk lol ANYWAY HAVE A GREAT DAY!

topjm [15]

Answer:

okie then you too

5 0

3 years ago

A 2.00 liter evacuated container has a mass of 1050.0 g. When the container is filled with an unknown gas at 800. mm Hg pressure

Andrei [34K]

Answer:

(A) 28

Explanation:

To solve this problem we use the PV=nRT equation, where:

P = 800 mmHg ⇒ 800/760 = 1.05 atm

V = 2.00 L

n = ?

R = 0.082 atm·L·mol⁻¹·K⁻¹

T = 25.0 °C ⇒ 25.0 + 273.16 = 298.16 K

We input the data:

1.05 atm * 2.00 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 298.16 K

And solve for n:

n = 0.086 mol

Now we calculate the gas' mass:

Gas Mass = (Mass of Container w/ Gas) - (Mass of Empty Container)

Gas Mass = 1052.4 g - 1050.0 g = 2.4 g

Finally we calculate the unknown gas' molar mass, using its mass and its number of moles:

Molar Mass = mass / moles

Molar Mass = 2.4 g / 0.086 mol = 27.9 g/mol

So the answer is option (A).

5 0

3 years ago

Match the description to the type of mixture.

Softa [21]

Answer:

1-homo

2-hetero

3-hetero

4-homo

Explanation:

7 0

2 years ago

A 10.00 mL sample of vinegar (an aqueous solution of acetic acid) is titrated with 0.5062 M NaOH(aq) and 16.58 mL is required to

sammy [17]

Answer:

5.01%

Explanation:

Density of vinegar = mass/volume

Mass of 10.00 mL = density x volume

= 1.006 x 10 = 10.06 g

From the equation of reaction:

$CH_3COOH(aq)+NaOH(aq)-->CH_3COONa(aq)+H_2O(l)$

1 mole pf CH3COOH requires 1 mole of NaOH for neutralization.

mole of NaOH = molarity x volume

= 0.5062 x 0.01658

= 0.008392796‬ mole

0.008392796‬ mole of NaOH will therefore require 0.008392796‬ mole of CH3COOH.

mass of CH3COOH = mole x molar mass

= 0.008392796‬ x 60.052

= 0.504 g

Percentage by mass of acetic acid in the vinegar = 0.504/10.06 x 100%

= 5.01%

The percent by mass of acetic acid in the vinegar is 5.01%

3 0

2 years ago

If an atom has 35 protons in the nucleus, how many will it have orbiting nucleus

yan [13]

It will have 35 ''electrons'' . Basically the number of protons in the nucleus of an atom is always equal to the number of electrons but its just that protons are positively charged and electrons are negatively charged.

8 0

3 years ago