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1 year ago

Hi!! please help :( lots of points !

Chemistry

1 answer:

andreev551 [17]1 year ago

3 0

Answer:

Structure:

Differences- A polymer is a collection of a large number of molecules whereas a monomer is a single molecule.

A monomer is a single molecule, which has the ability to chemically bond with other monomers in a long chain. A polymer is a chain that is made when monomers bind with other monomers.

Similarities- They are both molecules

Properties:

Differences- Monomers have polyfunctionality, which is the capacity to form chemical bonds to at least two other monomer molecules. Polymers are chemically unreactive, solids at room temperature, malleable, tough, and are electrical insulators.

Similarities- They both makeup larger forms of matter.

Intermolecular Forces

Differences: Polymers are held together by covalent bonds, hydrogen bonds, and dispersion bonds. Monomers are only held together by hydrogen bonds.

Similarities: They can both be bonded together by hydrogen bonds.

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IRINA_888 [86]

Answer:

A) Sample B has more calcium carbonate molecules

Explanation:

M = Molar mass of calcium carbonate = 100.0869 g/mol

$N_A$ = Avogadro's number = $6.022\times 10^{23}\ \text{mol}^{-1}$

For the 4.12 g sample

Moles of a substance is given by

$n=\dfrac{m}{M}\\\Rightarrow n=\dfrac{4.12}{100.0869}\\\Rightarrow n=0.0411\ \text{mol}$

Number of molecules is given by

$nN_A=0.0411\times 6.022\times 10^{23}=2.48\times 10^{22}\ \text{molecules}$

For the 19.37 g sample

$n=\dfrac{19.37}{100.0869}\\\Rightarrow n=0.193\ \text{mol}$

Number of molecules is given by

$nN_A=0.193\times 6.022\times 10^{23}=1.16\times 10^{23}\ \text{molecules}$

$1.16\times 10^{23}\ \text{molecules}>2.48\times 10^{22}\ \text{molecules}$

So, sample B has more calcium carbonate molecules.

The ratio of the elements of carbon, oxygen, calcium atoms, ions, has to be same in both the samples otherwise the samples cannot be considered as calcium carbonate. Same is applicable for impurities. If there are impurites then the sample cannot be considered as calcium carbonate.

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Explanation:

I got it right :))

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