If it takes 3.4s for the egg to fall, how high was it
1 answer:
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Answer:
v₂ = 5131.42 m/s
Explanation:
given,
radius of the planet = r₁ = 9.00×10⁶ m
mass of the satellite = m₁ = 68 Kg
orbital radius = r₁ = 8 x 10⁷ m
orbital speed = v₁ = 4800 m/s
mass of second satellite = m₂ = 84.0 kg
orbital radius = r₂ = 7.00×10⁷ m
orbital speed of second satellite = v₂ = ?
using orbital speed of satellite
so,
now,
v₂ = 5131.42 m/s
The orbital speed of second satellite is equal to v₂ = 5131.42 m/s