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Leno4ka [110]
3 years ago
14

Which term does this explain?

Physics
1 answer:
AlladinOne [14]3 years ago
5 0
It is a fact because I just want to post a question man so I have to answers something pp poop
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In a crossing situation, which vessel is required to maintain its course and speed?
makvit [3.9K]

Both in the domestic and international guidelines tell that when two power-driven vessels are crossing so as to contain risk of collision, the vessel which has the other on her starboard side (the give-way vessel) must keep out of the way.

If you are the give-way vessel, it is your responsibility to avoid a collision. Normally, this means you must change speed or direction to cross behind the other vessel which is the stand-on vessel.

At evening, when you perceive a red light crossing right-to-left in front of you, you need to change your course. But if you perceive a green light crossing from left-to-right, you are the stand-on vessel, and should maintain course and speed.

The leading situations of collision risk are meeting head-on, overtaking, and crossing. When one of two vessels is to keep out of the way (give-way vessel), the other, the stand-on vessel, must uphold course and speed.

3 0
3 years ago
Why are vectors important in physics?
quester [9]
They are quantities with magnitude and direction like velocity, we'd be doomed without them to be honest , just knowing how fast something is going isn't enough, you want to know where it is going
7 0
4 years ago
Elements on the periodic table are organized by atomic number and then by __________ additional ways.
PtichkaEL [24]
Answer:B.2
Explaination

3 0
3 years ago
Read 2 more answers
you are designing an airport for small planes. one kind of airplane that might use this airfield must reach a speed before takeo
denis23 [38]

(a)The required speed for take off will be 24.49 m/sec.

(b)The minimum length must the runway have 193 m.

<h3>What is speed?
</h3>

Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity. it is denoted by u for the initial speed while v for the final speed. its SI unit is m/sec.

(a)The required speed for take off will be 24.49 m/sec.

From the Newtons third equation of motion;

\rm  v^2 = u^2+2as \\\\ v=0+2 \times 2 \times 150 \\\\ v=\sqrt{600}\\\\ v=24.49 \ m/sec

Hence, the required speed for take off will be 24.49 m/sec.

(b)The minimum length must the runway have 193 m.

From the Newtons third equation of motion;

\rm v^2 = u^2+2as \\\\ (27.78)^2 = 0+2\times 2 s \\\\\ s=192.93 \ m

Hence, the minimum length must the runway have 193 m.

To learn more about the speed, refer to the link;

brainly.com/question/7359669

#SPJ1

7 0
2 years ago
Find the distance between each pair of points.
s344n2d4d5 [400]

The distances are:

- E and F: 4 units.

- C and D: 5 units.

- G and H: 3 units.

- A and B: 6 units.

Why?

We can find the distance between each pair of points using the following formula:

d(P_1,P_2)=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

So, calculating we have:

- E(-2, -1) and F(-2, -5):

d(E,F)=\sqrt{(-2-(-2))^{2}+(-5-(-1))^{2}}\\\\d(E,F)=\sqrt{0+(-5+1)^{2}}=\sqrt{0+(-4)^{2}}=\sqrt{16}=4units

- C(-4, 1) and D(1, 1):

d(C,D)=\sqrt{(1-(-4))^{2}+(1-(1))^{2}}\\\\d(C,D)=\sqrt{(5)^{2}+0^{2}}=\sqrt{25+0}=\sqrt{25}=5units

- G(3, -5) and H(6, -5):

d(G,H)=\sqrt{(6-(3))^{2}+(-5-(-5))^{2}}\\\\d(G,H)=\sqrt{(3)^{2}+0^{2}}=\sqrt{9+0}=\sqrt{9}=3units

- A(5, 4) and B( 5, -2):

d(A,B)=\sqrt{(5-(5))^{2}+(-2-(4))^{2}}\\\\d(A,B)=\sqrt{0+(-6)^{2}}=\sqrt{0+36}=\sqrt{36}=6units

Have a nice day!

8 0
3 years ago
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