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fenix001 [56]
3 years ago
11

How do you find solubility? I am given only the temperature and the substance is KNO3. I don’t need anyone to solve it for me, j

ust give me a formula. Thank you!
Chemistry
1 answer:
skad [1K]3 years ago
5 0
There’s no formula that relates solubility to temperature, but you can look up the solubility constant Ksp of substance given and then take the square root of that to find solubility.
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Calculate the osmotic pressure of a solution containing 24.6g of glycerin in 250ml of solution at 298K
gavmur [86]
The formula to calculate osmotic pressure is 
Osmotic Pressure = M R T
M = Molarity
R = Ideal Gas Constant
T = Temperature in Kelvin

So, 
24.6/.2254kg=109.139g /kg  >>>>> Molarity
109.139 x mols/92 g = 1.186 mols kg^-1
1.186 x 0.08134 x 298 K = 28.755 atm
<span>1.06852 x 0.08134 x 298K= 26.5 atm

The answer is 26.5</span>
6 0
3 years ago
Which of the following is an accurate example of how the water cycle can influence local weather? A. An increase in evaporation
irina1246 [14]

The answer is; A

During a hot day, the land heats up faster than the waters. The air on land becomes warm and less dense fast and begin to rise in the atmosphere. The air on the ocean with is still cooler and denser moves in to replace the rising on land air. This causes a sea breeze. The sea breeze carries with it, moisture. The hotter the day the higher the humidity. When the air goes inland, it causes precipitation when it rises,  cool, and condenses.


3 0
3 years ago
Read 2 more answers
2.The rate constant of a first order reaction is 66 s-1. What is the rate constant in units of minutes
Vanyuwa [196]

Answer:

66s^-1 will be 1/66

then to convert to minute you multiply by 69

1/66 x 60 = 3960 mins

4 0
2 years ago
Be sure to answer all parts. Write the equations representing the following processes. In each case, be sure to indicate the phy
barxatty [35]

Answer:

1.S^{-}(g)+e^{-} \rightarrow S^{2-}(g)

2.Ti^{2+}(g) \rightarrow Ti^{3+}(g) \,\, IE = 2652.5\,kJ.mol^{-1}

3.The electron affinity of  Mg^{2+} is zero.

4.O^{2-}(g) \rightarrow O^{-}(g)+e^{-}

Explanation:

1.

<u>Electron affinity:</u>

It is defined as the amount of energy change when an electron is added to atom in the gaseous phase.

The electron affinity of S^{-} is as follows.

S^{-}(g)+e^{-} \rightarrow S^{2-}(g)

2.

<u>Ionization energy</u>:

Amount of energy required to removal of an electron from an isolated gaseous atom.

The third ionization energy of Titanium is as follows.

Ti^{2+}(g) \rightarrow Ti^{3+}(g) \,\, IE = 2652.5\,kJ.mol^{-1}

3.

The electronic configuration of Mg: 1s^{2}2s^{2}2p^{6}3s^{2}

By the removal of two electrons from a magnesium element we get Mg^{2+} ion.

Mg^{2+} has inert gas configuration i.e,1s^{2}2s^{2}2p^{6}

Hence, it does not require more electrons to get stability.

Therefore,the electron affinity of  Mg^{2+} is zero.

4.

The ionization energy of O^{2-} is follows.

O^{2-}(g) \rightarrow O^{-}(g)+e^{-}

3 0
3 years ago
What mass (in grams) of silver contains the same number of atoms as 5.59 grams of sulfur?
Amanda [17]

Answer:

18.84 g of silver.

Explanation:

We'll begin by calculating the number atoms present in 5.59 g of sulphur. This can be obtained as follow:

From Avogadro's hypothesis,

1 mole of sulphur contains 6.02×10²³ atoms.

1 mole of sulphur = 32 g

Thus,

32 g of sulphur contains 6.02×10²³ atoms.

Therefore, 5.59 g of sulphur will contain = (5.59 × 6.02×10²³) / 32 = 1.05×10²³ atoms.

From the calculations made above, 5.59 g of sulphur contains 1.05×10²³ atoms.

Finally, we shall determine the mass of silver that contains 1.05×10²³ atoms.

This is illustrated below:

1 mole of silver = 6.02×10²³ atoms.

1 mole of silver = 108 g

108 g of silver contains 6.02×10²³ atoms.

Therefore, Xg of silver will contain 1.05×10²³ atoms i.e

Xg of silver = (108 × 1.05×10²³)/6.02×10²³

Xg of silver = 18.84 g

Thus, 18.84 g of silver contains the same number of atoms (i.e 1.05×10²³ atoms) as 5.59 g of sulfur

7 0
2 years ago
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