In ionic bond there is the formation of ions due to transfer of electrons from one atom<span> to </span>the other. Normally, at this link, there is an element that tends to yield electrons (metal-cation), and one that tends to receive electrons (not metal-anion).
Note: the Ionic bond is the only in the transfer of electrons<span>.</span>
Answer:
12 L of 40% sulfuric acid solution and 8 L of 10% sulfuric acid solution are needed to make 20 L of sulfuric acid solution.
Explanation:
For first solution of sulfuric acid :
C₁ = 40% , V₁ = ?
For second solution of sulfuric acid :
C₂ = 10% , V₂ = ?
For the resultant solution of sulfuric acid:
C₃ = 28% , V₃ = 20L
Also,
<u>V₁ + V₂ = V₃ = 20L</u> ......................................(1)
Using
<u>C₁V₁ + C₂V₂ = C₃V₃</u>
<u>40×V₁ + 10×V₂ = 28×20</u>
So,
40V₁ + 10V₂ = 560........................................(2)
Solving 1 and 2 as:
V₂ = 20 - V₁
Applying in 2
40V₁ + 10(20 - V₁) = 560
40V₁ + 200 - 10V₁ = 560
30V₁ = 360
<u>V₁ = 12 L</u>
So,
<u>V₂ = 20 - V₁ = 8L</u>
<u><em>12 L of 40% sulfuric acid solution and 8 L of 10% sulfuric acid solution are needed to make 20 L of sulfuric acid solution.</em></u>
<span>79.70 grams
First, calculate the molar mass of Na2CO3 by looking up the molar mass of the elements used in it.
Sodium = 22.989769
Carbon = 12.0107
Oxygen = 15.999
Multiply each molar mass by the number of atoms used, and sum the results to get the molar mass
2 * 22.989769 + 12.0107 + 3 * 15.999 =105.9872
Finally, multiply the molar mass by the number of moles you need.
0.752 * 105.9872 = 79.7024 grams</span>
The reaction of benzene with an alkyl chloride and aluminum trichloride is called a Friedel-Crafts alkylation. The aluminum trichloride is a lewis acid that reacts with the alkyl chloride, and this converts the alkyl group into a very good electrophile. The overall reaction is an electrophilic aromatic substitution. A pi bond of the benzene ring will attack the electrophile as a nucleophile and form a new carbon-carbon bond. The result is a monosubstituted isopropyl group on the benzene ring.
However, we are told that the conditions are set up to encourage dialkylation. The isopropyl group is a group that donates electron density through induction. Therefore, it is an ortho- and para-directing group. This means that once one isopropyl group is substituted on to the benzene ring, the second substitution will be favoured in the ortho- and para-positions. In this instance, the major product is the 1,4-disubstituted product. The reason being is that the isopropyl groups are very bulky, and the steric hindrance of having two isopropyl groups adjacent leads to a small amount of this product being formed.
There will also be trace amounts of the meta-substituted product, but the 1,4- and 1,2-substituted products are more favoured.
Answer: D. MIXTURE
Explanation:
It’s important, you first understand the meaning of a pure substance, an element, a compound and a mixture.
A pure substance is a material with a particular composition and consists of only one type of atom or compound. An example is pure sugar.
An element is a substance that cannot be broken down chemically and elements have just one symbol from the periodic table such as Carbon (C), Hydrogen (H).
A compound consists of two or more elements that are bonded chemically. For example, ammonia is a compound with a chemical formula NH3 which means it is means it is made up of 3 moles of Hydrogen and 1 mole of nitrogen.
A mixture contains two or more elements or compounds that are not bonded chemically. It can homogenous or heterogeneous. Examples are salt solution, sand, vinegar.
Vinegar is a mixture of two compounds water and acetic acid and can be separated by physical means because no chemical bond exists between water and acetic acid.