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s344n2d4d5 [400]
2 years ago
5

express in word equation and chemical equation of the chemical reaction when potassium chlorate is heated.​

Chemistry
1 answer:
IgorLugansk [536]2 years ago
8 0

Answer:

Word equation: <u>Potassium chlorate → Potassium chloride + Oxygen</u>

Chemical equation: <u>KClO₃ → KCl + O₂</u>

Explanation:

<em>This is decomposition reaction so there will only be one reactant, which is potassium chlorate.</em>

The chemical equation will be:

KClO₃ → KCl + O₂

The balanced equation would be:

2KClO₃ → 2KCl + 3O₂

The word equation will be:

Potassium chlorate → Potassium chloride + Oxygen

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Calculate the percentage of the void space out of the total volume occupied by 1 mole of water molecules. The density of water i
gtnhenbr [62]

Answer:

The percentage of the void space out of the total volume occupied is 93.11%

Explanation:

A mole of water contains 2 atoms of hydrogen and 1 atom of oxygen.

To calculate the volume of a mole of water, we calculate 2 times the volume of the hydrogen atom and 1 times the volume of the oxygen atom

Let's calculate this one after the other.

For the hydrogen, formula for the volume will be

V_{hydrogen = 2 × 4/3 × π × r_{H}^{3}

where r_{H}^{3} = 37 pm which is read as 37 picometer (1 picometer = 10^-12 m) = 37 × 10^{-12} meters

Volume of the hydrogen = 8/3 × (37 × 10^-12)^3 = 4.05 * 10^-31

we multiply this by the avogadro's number = 6.02 * 10^23

= 4.05 * 10^-31 * 6.02 * 10^23 = 2.6 * 10^-8 m^3

We do same for thr oxygen, but this time we do not multiply the volume of the oxygen by 2 as we have only one atom of oxygen

Volume of oxygen = 4/3 * π * (73 * 10^-12) ^3 * avogadro's number = 9.81 * 10^-7 m^3

adding both volumes together, we have 1.24 * 10^-6 m^3 or simply 1.24 ml ( 0.01 m = 1 ml)

Dividing the molar mass of one mole of water by its density, we can get the volume of 1 mole of water

= (18g/mol)/(1 g/ml) = 18 ml/mol

Now we proceed to calculate the volume of void = Total volume - volume of molecule = 18 - 1.24 = 16.76 ml

Now, the percentage of void = volume of void/total volume * 100%

= 16.76/18 * 100% = 93.11%

7 0
3 years ago
All of the cells in the body need oxygen. Hemoglobin molecules in red blood cells transport oxygen through the bloodstream. Oxyg
tankabanditka [31]

Answer:

High partial pressure of oxygen in the tissues.

Explanation:

Hemoglobin is a protein found in the red blood cells that is responsible for the transportation of oxygen from the lungs to the rest of the tissues in the body. The partial pressure determines whether oxygen is loaded or unloaded into the hemoglobin.

When there is lack of oxygen in our bodies, we experience hypoxia.

6 0
3 years ago
If a snack cake contains 450 food calories and Carla
Oksana_A [137]

Answer:

9/10hr

Explanation:

From the question given:

Carla was able to burn 250 calories by running for one-half (1/2)hr.

Therefore, Carla will burn 450calories by running for = (450x1/2) /250 = 225/250 = 9/10hr

8 0
3 years ago
If the initial concentration of SO2Cl2 is 0.125 M , what is the concentration of SO2Cl2 after 210 s ?
andre [41]

Complete question:

The decomposition of SO2Cl2 is first order in SO2Cl2 and has a rate constant of 1.44×10⁻⁴ s⁻¹ at a certain temperature.

If the initial concentration of SO2Cl2 is 0.125 M , what is the concentration of SO2Cl2 after 210 s ?

Answer:

After 210 s the concentration of SO2Cl2  will be 0.121 M

Explanation:

ln\frac{[A_t]}{[A_0]} =-kt

where;

At is the concentration of A at a time t

A₀ is the initial concentration of A

k is rate constant = 1.44×10⁻⁴ s⁻¹

t is time

ln(At/A₀) = -( 1.44×10⁻⁴)t

ln(At/0.125) =  -( 1.44×10⁻⁴)210

ln(At/0.125) = -0.03024

\frac{A_t}{0.125} = e^{-0.03024

At/0.125 = 0.9702

At = 0.125*0.9702

At = 0.121 M

Therefore, after 210 s the concentration of SO2Cl2  will be 0.121 M

6 0
3 years ago
A conjugate base is the species that
malfutka [58]
A conjugate base is the species that D. Remains after an acid has given up a single proton.

It is the deprotonated form of the acid.
8 0
3 years ago
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