Answer:
The correct answer is-
F1 - AaBb (lacerate)
F2 - A_B_; A_bb; and aaB_ (lacerate)
- aabb (normal)
2. Two genes, with a dominant allele at either or both loci.
Explanation:
The given information gives THE following data:
Dominant: Lancerate leaves - AABB
Recessive: normal leaves - aabb
F1 has - all Lacerated leaves - AaBb
F2 by selfing F1:
AB Ab aB ab
AB AABB AABb AaBB AaBb
Ab AABb AAbb AaBb Aabb
aB AaBB AaBb aaBB aaBb
ab AaBb Aabb aaBb aabb
Here, 15/16 = lacerate which is 0.94 which is equal to the value of lacerate given in the question - 249/265 = 0.94
And normal 1/16 = 0.062 is almost same as 16/265 = 0.060
Thus, the genotypes of -
F1 - AaBb (lacerate)
F2 - A_B_; A_bb; and aaB_ (lacerate)
- aabb (normal)
Answer:
A. organ.. B. Species
Explanation:
1. parts that make up organism are called as organs
2. a group of similar organisms that can successfully interbreed called as species.
In DNA, there is a code for the sequence
of three bases for the placement of certain amino acid in a protein chain.<span> The amino acid chain that can be produced by
the DNA base sequence of C-A-A-G-T-T-A-A-A-T-T-A-T-T-G-T-G-A would be based on
the DNA code CAA is valine, GTT is glutamine, AAA is phenylalanine, TTA is asparagine,
TTG is asparagine and TGA is threonine. </span>
Answer:
If a DNA molecule has 30% Adenine the percentage of the other bases is Thymine: 30% Cytosine: 20% Guanine: 20%.
Explanation:
When the percentage that a base has in a DNA molecule is given, the percentage of the other bases can be known using the Chargaff's base pair rule.
A DNA molecule has the information of the genome of a living being, according to a specific sequence of its nitrogenous bases adenine, guanine, cytosine and thymine.
Chargaff was able to establish that in a DNA molecule the ratio of purine : pyrimidine of 1:1, so there must be the same amount of thymine as adenine and a similar amount of guanine for the cytosine, taking into account the complementarity of bases.
Taking into account the law of the base pair, if in a DNA chain there is 30% of Adenine, in the molecule there is:
- <em>Adenine 30%.
</em>
- <em>Thymine 30%.
</em>
- <em>Cytosine 20%.
</em>
- <em>Guanine 20%.
</em>
- <em>Total ..... 100%
</em>
In this case, the <u>Chargaff rule is useful to determine the percentage of nitrogenous bases that exist in a DNA molecule, knowing the percentage of a single base</u>.
