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3 years ago

Agricultural waste used as a fuel is an example of

2 answers:

6 0

<span>Agricultural waste used as a fuel is an example of biofuels, there already different kinds of biofuels that came from agricultural waste, the most common are the biogas and bioethanol. biogas are produce when agricultural waste such as poultry manures and grassy waste are fermented to create biogas. while biothanol uses sugar rich agricultural waste to make ethanol</span>

jeka57 [31]3 years ago

3 0

biofuels is the answer to your question

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You pull on a crate using a rope as in (Figure 1), except the rope is at an angle of 20.0 ∘ above the horizontal. The weight of

Nezavi [6.7K]

Hi there!

For an object on an incline with friction being pulled, the following forces are present.

Force due to Gravity
Force due to Friction
Force due to tension

The force due to friction opposes the force due to gravity which would cause the object to slide down. (The force due to friction acts up the incline). Additionally, the force due to the rope is also upward.

Let up the incline be positive, and down the incline be negative.

Doing a summation of forces:
$\Sigma F = F_T + F_f - F_g$

For the crate to be moving at a constant velocity, there is NO net force acting on the crate, so:
$0 = F_T + F_f - F_g$

Now, we can express each force as an equation.

Force due to tension:

Must be solved for.

Force due to gravity:

On an incline, this is equivalent to the SINE component of its weight. (Force of gravity is STILL THE WEIGHT, but on an incline, it contains a horizontal component that contributes to the net force)

This is expressed as:
$F_g = Mgsin\theta$

Force due to friction:

Equivalent to the normal force and coefficient of friction. The normal force is the VERTICAL component of the object's weight, so:

$N = Mgcos\theta$

$F_f = \mu Mgcos\theta$

Now, plug these expressions into the above equation.

$0 = F_T + \mu Mgcos\theta - Mgsin\theta\\\\Mgsin\theta - \mu Mgcos\theta = F_T$

Mg = 245 N (weight). Plug in all values:
$245sin(20) - 0.270(245)cos(20) = F_T\\\\F_T = \boxed{21.634 N}$

The normal force is equivalent to the vertical component (PERPENDICULAR TO THE INCLINE) of the weight (cosine), so:

$N = Mgcos\theta\\\\N = 245cos(20) = \boxed{230.225 N}$

5 0

2 years ago

When velocity is graphed with respect to time, what does the area under

Juliette [100K]

Answer:

the answer is D

Explanation:

Since the velocity of the object is the derivative of the position graph, the area under the line in the velocity vs. time graph is the displacement of the object.

4 0

3 years ago

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Why are the loops on a roller coaster tear-drop shaped instead of circular? It would be simpler to design & build tracks wit

VLD [36.1K]

The centripetal force acting on the rider is much greater if the roller coaster has a circular loop, rather than oval. This is because the change in direction is much sharper throughout the loop, causing the rider to experience a much more intense G-Force throughout the loop.
A teardrop loop features a more gradual change of direction: the cart spends time moving upward, briefly changes direction, and spends the rest of the time moving downward and flattening to a horizontal path. This means the riders experience the majority of the force on the way down as the car levels out, rather than an intense G-force throughout the ride.

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3 years ago

Please help, very confused!

PtichkaEL [24]

D. the last choice because the info above tells u so

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3 years ago

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3 What is the displacement of a satellite when it makes a complete round along its circular path?

kirill [66]

Answer:

Explanation: