Hi there!
For an object on an incline with friction being pulled, the following forces are present.
- Force due to Gravity
- Force due to Friction
- Force due to tension
The force due to friction opposes the force due to gravity which would cause the object to slide down. (The force due to friction acts up the incline). Additionally, the force due to the rope is also upward.
Let up the incline be positive, and down the incline be negative.
Doing a summation of forces:

For the crate to be moving at a constant velocity, there is NO net force acting on the crate, so:

Now, we can express each force as an equation.
Force due to tension:
Force due to gravity:
- On an incline, this is equivalent to the SINE component of its weight. (Force of gravity is STILL THE WEIGHT, but on an incline, it contains a horizontal component that contributes to the net force)
This is expressed as:

Force due to friction:
- Equivalent to the normal force and coefficient of friction. The normal force is the VERTICAL component of the object's weight, so:


Now, plug these expressions into the above equation.

Mg = 245 N (weight). Plug in all values:

The normal force is equivalent to the vertical component (PERPENDICULAR TO THE INCLINE) of the weight (cosine), so:

Answer:
the answer is D
Explanation:
Since the velocity of the object is the derivative of the position graph, the area under the line in the velocity vs. time graph is the displacement of the object.
The centripetal force acting on the rider is much greater if the roller coaster has a circular loop, rather than oval. This is because the change in direction is much sharper throughout the loop, causing the rider to experience a much more intense G-Force throughout the loop.
A teardrop loop features a more gradual change of direction: the cart spends time moving upward, briefly changes direction, and spends the rest of the time moving downward and flattening to a horizontal path. This means the riders experience the majority of the force on the way down as the car levels out, rather than an intense G-force throughout the ride.
D. the last choice because the info above tells u so
Answer:
0
Explanation:
The displacement is zero since it goes in a full circle and ends up where it started.