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AysviL [449]
3 years ago
12

The average sound intensity inside a busy restaurant is 3.10 10-5 W/m2. How much energy goes into each ear (area = 2.1 10-3 m2)

during a 1 hour meal?

Physics
2 answers:
larisa [96]3 years ago
8 0

Explanation:

Below is an attachment containing the solution.

vichka [17]3 years ago
6 0

Answer:

2.344×10⁻⁴ J

Explanation:

Energy: This can be defined as the ability or the capacity to do wok.

The S.I unit of energy is Joule(J).

From the question,

E = P×t.............. Equation 1

Where E = amount of energy that goes into the ear, P = power, t = time.

But,

P = I×A.............. Equation 2

Where I = sound intensity, A = cross sectional area.

Substitute equation 2 into equation 1

E = I×A×t................ Equation 3

Given: 3.1×10⁻⁵ W/m², A = 2.1×10⁻³ m², t = 1 hour = 1×60×60 =  3600 s

Substitute into equation 3

E = 3.1×10⁻⁵× 2.1×10⁻³× 3600

E = 2.344×10⁻⁴ J.

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Color is what scientist use to determine the temperature of a star!

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4 0
3 years ago
The sum of the kinetic and potential energies of a system of objects is conserved: Group of answer choices only when no external
uysha [10]

The sum of the kinetic and potential energies of a system of objects is conserved only when no external force acts on the objects.

<h3>Conservation of mechanical energy</h3>

The principle of conservation of mechanical energy states that the total mechanical energy of an isolated system (absence of external force) is always constant.

M.A = P.E + K.E

where;

P.E is potential energy

K.E is kinetic energy

Thus, the sum of the kinetic and potential energies of a system of objects is conserved only when no external force acts on the objects.

Learn more about conservation of mechanical energy here: brainly.com/question/24443465

7 0
2 years ago
A contact force exists between two interacting objects that physically contact each other. a non-contact force exists when two i
Murrr4er [49]
True.

A contact force is a force between two objects that are physically in contact with each other: an example of a contact force is the normal reaction of a table supporting a book.

A non-contact force is a force between two objects that are not physically in contact with each other: an example of non-contact force is the gravitational attraction between the Earth and the Moon.
4 0
3 years ago
Read 2 more answers
A football is thrown horizontally with an initial velocity of(16.6 {\rm m/s} ){\hat x}. Ignoring air resistance, the average acc
Ray Of Light [21]

Answer:

A) 16.6 m/s i -17.2 m/s j B) 23.9 m/s  c) 46º below horizontal.

Explanation:

A) Once released, the football is not under the influence of any external force in the horizontal direction, so it  continues moving at a constant speed equal to the initial velocity, i.e., 16.6 m/s.

If we choose the horizontal direction to be coincident with the x-axis, and make positive the direction towards the right (assuming that  this was the direction along which the football was thrown), we can write the horizontal component of the veelocity vector, as follows:

vₓ = 16.6 m/s i

In the vertical direction, the football, once released, is in free fall, starting from rest.

So, we can find the vertical component of the velocity vector, at a given point in time, applying the definition of acceleration, as follows:

vy = a*t = -g*t = -9.81 m/s²*1.75 s = -17.2 m/s

Assuming that the upward direction is the positive  for the y-axis (perpendicular to the chosen  x-axis), we can write the vertical component of  the velocity vector, at t=1.75 s, as follows:

vy = -17.2 m/s j

So, the velocity vector, in terms of the unit vectors i and j, can be written in this way:

v = 16.6 m/s i -17.2 m/s j

b) The magnitude of this vector can be found applying trigonometry, as the magnitude is the hypotenuse of a triangle with sides equal to vx and vy, as follows:

v =\sqrt{(16.6m/s)^{2}+ (-17.2m/s)^{2}} = 23.9 m/s

v = 23.9 m/s

c) The direction of the vector (below the horizontal) can be found as the angle which tangent is given by the quotient between vy and vx, as follows:

tg θ =\frac{-17.2}{16.6} =-1.036

⇒ θ = tg⁻¹ (-1.036) = 46º below horizontal.

6 0
3 years ago
Which formula can be used to solve problems related to the first law of thermodynamics?
docker41 [41]

Answer: The formula used to solve the problems related to first law of thermodynamics is \Delta U=Q+W

Explanation:

First law of thermodynamics states that the total energy of the system remains conserved. Energy can neither be destroyed, nor be created but it can only be transformed into one form to another.

Its implication is any change in the internal energy will be either due to heat energy or work energy.

Mathematically,

\Delta U=Q+W

where, Q = heat energy

W = work energy

\Delta U = Change in internal energy

Sign convention for these energies:

For Q: Heat absorbed will be positive and heat released will be negative.

For W: Work done by the system is negative and work done on the system is positive.

For \Delta U: When negative, internal energy is decreasing and when positive, internal energy is increasing.

Hence, the formula used to solve the problems related to first law of thermodynamics is \Delta U=Q+W

8 0
3 years ago
Read 2 more answers
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