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AysviL [449]
3 years ago
12

The average sound intensity inside a busy restaurant is 3.10 10-5 W/m2. How much energy goes into each ear (area = 2.1 10-3 m2)

during a 1 hour meal?

Physics
2 answers:
larisa [96]3 years ago
8 0

Explanation:

Below is an attachment containing the solution.

vichka [17]3 years ago
6 0

Answer:

2.344×10⁻⁴ J

Explanation:

Energy: This can be defined as the ability or the capacity to do wok.

The S.I unit of energy is Joule(J).

From the question,

E = P×t.............. Equation 1

Where E = amount of energy that goes into the ear, P = power, t = time.

But,

P = I×A.............. Equation 2

Where I = sound intensity, A = cross sectional area.

Substitute equation 2 into equation 1

E = I×A×t................ Equation 3

Given: 3.1×10⁻⁵ W/m², A = 2.1×10⁻³ m², t = 1 hour = 1×60×60 =  3600 s

Substitute into equation 3

E = 3.1×10⁻⁵× 2.1×10⁻³× 3600

E = 2.344×10⁻⁴ J.

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Answer:

The energy entering, reflecting, absorbed, and emitted by the earth system are the components of the Earth's radiation budget.

Explanation:

I hope this helps also I hope you have a great day and a new year.

4 0
2 years ago
A wire 6.60 m long with diameter of 2.05 mm has a resistance of 0.0310 Ω.
Alex73 [517]

Answer:

1.551×10^-8 Ωm

Explanation:

Resistivity of a material is expressed as shown;.

Resistivity = RA/l

R is the resistance of the material

A is the cross sectional area

l is the length of the wire.

Given;

R = 0.0310 Ω

A = πd²/4

A = π(2.05×10^-3)²/4

A = 0.000013204255/4

A = 0.00000330106375

A = 3.30×10^-6m

l = 6.60m

Substituting this values into the formula for calculating resistivity.

rho = 0.0310× 3.30×10^-6/6.60

rho = 1.023×10^-7/6.60

rho = 1.551×10^-8 Ωm

Hence the resistivity of the material is 1.551×10^-8 Ωm

6 0
3 years ago
Gold has a density of 19300 kg/m³. Calculate the mass of 0.02 m³ of gold in kilograms.
hjlf

Answer:

Mass = 386 kg

Explanation:

<u><em>Density = Mass / Volume</em></u>

Mass = Density × Volume

Where D = 19300 kg/m³ , V = 0.02 m³

<em>Putting the given in the above formula</em>

Mass = 19300 × 0.02

Mass = 386 kg

7 0
2 years ago
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A 10.0kg water balloon is dropped from a height of 12.0m. Calculate the speed of the balloon just before it hits the ground
kolbaska11 [484]

Answer:

15.5 m/s.

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mgh = ½mv².

10* 10* 12= ½ *10 *v²

1200 = 5v²

v²=1200÷5

v=√240

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5 0
3 years ago
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--  Coal
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3 0
3 years ago
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