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3 years ago

A reason that one typically does not notice a blind spot in the visual field is that

Physics

1 answer:

Sophie [7]3 years ago

3 0

Explanation:

Both of our eyes have a blind spot, in the retina of eye where there are no rods (light vision) or cons (color vision) cells. Its about a size of pinhead. The blind spot is place where the optic nerves exit the eye and connect to our brain. The problem is that we cannot notice this blind as the brain fills in information for us.

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A 5000-kg freight car crashes into a 10,000-kg freight car at rest. They couple upon collision and move with a speed of 2 m/s. W

nirvana33 [79]

Answer:

6 m/s

Explanation:

mass of moving car m1=5000 kg

initial velocity of moving car vi1=?

mass of car at rest = m2=10000 kg

initial velocity of car at rest = vi2=0

final velcoities of both cars after collision = vf1=vf2= 2m/s

using conservation of momentum rule

m1vi1+m2vi2=m1vf1+m2vf2

putting values

==> 5000 × vi1 + 1000 × 0 = 5000 × 2 + 10000 × 2

==> 5000 ×vi1 = 2 × 15000

==> vi1 = 2 × 15000 ÷ 5000

==> vi1= 2×3=6 m/s

8 0

2 years ago

Newton's third law says that for every action force there is a reaction force which is

olga nikolaevna [1]

A. Equal and opposite For every action, there is an equal and opposite reaction

4 0

2 years ago

Thanks for answering

ElenaW [278]

Answer:

II) Kitchen waste: Meal leftovers, Banna peelings

Garden Waste: Camote leaves, Kangkong leaves, weeds

Factory: Glass bottles, carton pieces

III) A

IV) Home: Bottles of shampoo, leftover food, syringe

office Gloves

Classroom: containers

Laboratory: empty cartridge

5 0

2 years ago

A 1.2 x 103 kg racecar, with a velocity of 8 m/s, collides with an unsuspecting 80 kg honey badger who is standing

aalyn [17]

Answer: 90 m/s

Explanation:

Given

mass of racecar $M=1.2\times10^3\ kg$

velocity of racecar $u=8\ m/s$

mass of still honeybadger $m=80\ kg$

after collision race car is traveling at a speed of $v_1=2\ m/s$

conserving linear momentum

$Mu+m\times0=Mv_1+ mv_2\quad[v_2=\text{velocity of honeybadger after colllision}]$

$1.2\times10^3\times8+0=1.2\times10^3\times2+80\times v_2$

$1.2\times10^3(8-2)=80v_2\\v_2=\frac{7.2\times10^3}{80}=90\ m/s$

4 0

2 years ago

What is difference between kilowatt and kilowatt hour?

Scrat [10]

Those two units can be compared to a 'mile per hour' and a 'mile per hour - hour'.
One is a rate. The other is a quantity, after maintaining a rate for some time.

-- 'Joule' is a unit of energy. It's the amount of work (energy) you do
when you push with a force of 1 newton though a distance of 1 meter.
Lifting 10 pound of beans 3 feet off the floor takes about 40.7 joules of energy.

-- 'Watt' is a rate of using energy . . . 1 joule per second.
If you lift 10 pounds 3 feet off the floor in 1 second, your power is 40.7 watts.

-- 'Watt-second' is the amount of energy used in one second,
at the rate of 1 joule per second . . . 1 joule.

-- 'Watt-hour' is the amount of energy used in one hour,
at the rate of 1 joule per second . . . 3,600 joules.

-- 'Kilowatt' is a bigger rate of using energy . . . 1,000 joules per second.

-- 'Kilowatt - second' is the amount of energy used in one second,
at the rate of 1,000 joules per second . . . 1,000 joules .

-- 'Kilowatt - hour' is the amount of energy used in one hour,
at the rate of 1,000 joules per second . . . 3,600,000 joules .

Depending on where you live, 3,600,000 joules of energy bought
from the electric company costs something between 5¢ and 25¢.

6 0

2 years ago

Read 2 more answers