Period is 1/frequency
1/425 = 2.353ms
Answer:
The motorcycle travelled 69.73 m during these 3.1 s.
Explanation:
In order to calculate the distance that the motorcycle travelled we first need to obtain the acceleration rate that was used to brake the vehicle. We do that by using the following formula:
a = (V_final - V_initial)/(t) = (15 - 30)/(3.1) = -4.84 m/s^2
The distance is given by the following formula:
S = (V_final^2 - V_initial^2)/(2*a)
S = (15^2 - 30^2)/[2*(-4.84)] = (225 - 900)/(-9.68) = -675/(-9.68) = 69.73 m
The motorcycle travelled 69.73 m during these 3.1 s.
Power = work / time = 8000J / 20s = 400W
A, electromagnetic radiation
Formula for feild strength= F/q
q=7.0^10-5 coulombs
F=5.2 N
E=5.2 / 7.0^10-5
E=
