Answer:
5.648 N/C
Explanation:
Given:
q₁ = 60 pC/m² = 60 × 10⁻¹² C/m²
q₂ = -80 pC/m² = - 80 × 10⁻¹² C/m²
Now, 
Electric field is given as:
E = 
ε₀ = Permittivity of Free Space
thus, due to charge q₁ 
E₁ = 
or
E₁ = 3.389 N/C
and, due to charge q₂
E₂ = 
or
E₂ = 4.519 N/C
Now, 
The resultant electric field = 
or
The resultant electric field = 
or
The resultant electric field = 
or
The resultant electric field = 5.648 N/C