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3 years ago

What is the best Explanation for why a cell might shrivel

Chemistry

1 answer:

vova2212 [387]3 years ago

3 0

It means that the cell loses most of its water from osmosis when put in a hypertonic.

Hope that helps!

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In a titration of hno3, you add a few drops of phenolphthalein indicator to 50.00 ml of acid in a flask. You quickly add 20.00 m

bekas [8.4K]

Answer:

The HNO3 solution has a concentration of 0.07 M

Explanation:

Step 1: find a balanced equation

HNO3 (aq) + NaOH (aq) → NaNO3 (aq) + H2O (l)

⇒ for 1 mole of HNO3 reacted, there will also react 1 mole of NaOH, and be produced 1 mole of NaNO3 and 1 mole of H2O, since the ratio is 1:1

Step 2: Calculating moles

Since we know that for 1 mole of HNO3 there will react 1 mole of NaOH, we can calculate the number of moleNaOH

⇒ Concentration = mole / volume

⇒ 0.210 = mole / ((20 + 7.23 ml) *10^-3)

mole = 0.005733 mole NaOH = 0.005733 mole HNO3

Step 3: Calculating the concentration of HNO3

Concentration = mole / volume

C(HNO3) = 0.005733 mole / ((50 + 30 ml) *10^-3)

C(HNO3) = 0.07 M

The HNO3 solution has a concentration of 0.07 M

To control this we can calculate through the following formule:

0.02723L x 0.21 M x ( 1mol HNO3 / 1 mol NaOH) x (1/ 0.08L) = 0.07M

8 0

3 years ago

What does the arrow in chemical equations mean? (PLEASE HELP)

grin007 [14]

Answer:

yields

Explanation:

I just did that quiz on k12 8th grade

6 0

3 years ago

4 When the net force on an object is zero, we say that the two forces are:

AleksAgata [21]

Pretty sure it’s c hope this helps.

3 0

4 years ago

What does science mean to you?

DiKsa [7]

Answer:

The study of properties for all things living and non-living

8 0

3 years ago

In an experiment, 8.50 g of methane, CH4, was reacted with 15.9 g of oxygen gas to produce carbon dioxide and water. Determine t

exis [7]

Answer:

89.3 %

Explanation:

M(CH4) = 12+ 4*1 = 16 g/mol

M(O2) = 2*16 = 32 g/mol

M(CO2) = 12 + 2*16 = 44 g/mol

8.50 g * 1 mol/16 g = 0.5313 mol CH4

15.9 g * 1 mol/32 g = 0.4969 mol O2

9.77 g * 1 mol/44 g = 0.2220 mol CO2

1) CH4 + 2O2 -----> CO2 + 2H2O

from reaction 1 mol 2 mol

given 0.5313 mol (0.4969 mol)

1 mol CH4 --- 2 mol O2

0.5313 mol CH4 --- x mol O2

x= 2*0.5313 = 1.0626 mol O2

We can see that for given amount of CH4 we do not have enough O2, so O2 is a limiting reactant.

2) CH4 + 2O2 -----> CO2 + 2H2O

from reaction 2 mol 1 mol

given 0.4969 mol x mol

x = 0.4969*1/2 = 0.2485 mol CO2 theoretical yield

Practical yield CO2 = 0.2220 mol

Theoretical yield CO2 = 0.2485 mol

% yield = (0.2220/0.2485)*100% = 89.3 %

7 0

3 years ago