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dybincka [34]
2 years ago
15

A(n) ____________ is a push or a pull. newton acceleration force momentum

Chemistry
2 answers:
Advocard [28]2 years ago
3 0
The answer is force.

Hope this helps.
Maksim231197 [3]2 years ago
3 0

Answer:

Force

Explanation:

Any pull or push exerted on an object is force

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_____Mg + ____Fe2O3 → _____Fe + ____MgO
german

Answer:

3Mg + Fe₂O₃  → 2 Fe + 3MgO

Explanation:

Chemical equation;

Mg + Fe₂O₃  →  Fe + MgO

Balanced Chemical equation;

3Mg + Fe₂O₃  → 2Fe + 3MgO

This is the balanced equation. There are three magnesium, two iron and three oxygen atoms are on both side of equation thus it follow the law of conservation of mass.

Law of conservation of mass:

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

This law was given by french chemist  Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

7 0
3 years ago
Los fenomenos fisicos son cambios permamentes en la materia?
alexgriva [62]

Answer:

Explanation:

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5 0
3 years ago
K2CrO4 is added to a solution containing lead (II) and barium ions. If a precipitate is formed, what is it?
Step2247 [10]

Answer:

Lead (II) Chromate and Barium Chromate

Explanation:

5 0
2 years ago
What changes in color occur when bromine reacts with an alkene​
Gala2k [10]

Answer:

Explanation: Bromine, the dark red color disappears quickly as the atoms of bromine bond with the atoms of carbon in the double bond.

7 0
3 years ago
Copper has a specific heat of 0.385 J/gºC.
Anna71 [15]

Answer:

The final temperature is 348.024°C.

Explanation:

Given data:

Specific heat of copper = 0.385 j/g.°C

Energy absorbed = 7.67 Kj (7.67×1000 = 7670 j)

Mass of copper = 62.0 g

Initial temperature T1 = 26.7°C

Final temperature T2 = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

Q = m.c. ΔT

7670 J = 62.0 g × 0.385  j/g °C ×( T2- 26.7 °C )

7670 J = 23.87 j.°C ×( T2- 26.7 °C )

7670 J / 23.87 j/°C = T2- 26.7 °C

T2- 26.7 °C = 321.324°C

T2 = 321.324°C + 26.7 °C

T2 = 348.024°C

The final temperature is 348.024°C.

6 0
3 years ago
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