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3 years ago

The instantaneous velocity of an object is the blank of the object with a blank

Physics

1 answer:

miss Akunina [59]3 years ago

3 0

Instantaneous velocity is the velocity at a specific instant in time. I bet you are taking Honors Physics.

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passengers on an airplane move from rest to 73 meters per second before the airplane takes off. if the airplane takes 100 second

Brrunno [24]

Answer:

0.73m/s2

Explanation:

The speed at which the passengers move is the final speed of the plane

Hence acceleration = V-U/t; change in velocity and t is time taken. U is the initial velocity which is 0m/s

a = 73-0/100= 0.73m/s2

3 0

3 years ago

Find a unit vector normal to the plane containing Bold u equals 2 Bold i minus Bold j minus 3 Bold k and Bold v equals negative

Nastasia [14]

Answer:

$\hat{w}=\dfrac{\vec{5i+13j-k}}{13.92}$

Explanation:

It is given that,

$\vec{u}=2i-j-3k$

$\vec{v}=-3i+j-2k$

Taking the cross product of v and v such that,

$\vec{w}=u\times v$

$\vec{w}=(2i-j-3k)\times (-3i+j-2k)$

$\vec{w}=5i+13j-k$

$|w|=\sqrt{5^2+13^2(-1)^2}$

|w| = 13.92

Let $\hat{w}$ is the unit vector normal to the plane containing u and v. So,

$\hat{w}=\dfrac{\vec{w}}{|w|}$

$\hat{w}=\dfrac{\vec{5i+13j-k}}{13.92}$

Hence, this is the required solution.

7 0

3 years ago

When a 4.25 kg object is placed on top of a vertical spring, the spring compresses a distance of 2.62 cm. what is the force cons

ANTONII [103]

The force applied to the spring is the weight of the object that compresses it, so it is equal to:
$W=mg=(4.25 kg)(9.81 m/s^2)=41.7 N$

Because of this force, the spring compresses by $x=2.62 cm=0.0262 m$ . Using Hook's law,
$F=kx$ ,
since we know the intensity of the force (the weight W) and the compression of the spring, x, we can find k, the spring constant:
$k= \frac{F}{x}= \frac{W}{x}= \frac{41.7 N}{0.0262 m} =1591.6 N/m$

6 0

3 years ago

A+20 N force acts on a car and at the same time, a -30 N force acts on the

katovenus [111]

Answer:

-10 N, not balanced

Explanation:

Force is a vector quantity, so in order to find the net force on an object, we must use vector addition rule.

This means that if two forces acting on an object along the same line, we have to choose one direction as positive, and write the two forces with the correct sign.

In this problem, we have two forces acting along a line on the car:

- A first force of

$F_1 = +20 N$