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ohaa [14]
4 years ago
8

Check all that apply Which of the following are solutions to the equation below? 24x^2-47x+20=0 

Mathematics
1 answer:
g100num [7]4 years ago
6 0
It would be between a and e
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Subtract. (−8.3x+4)−(3.2x−5) Enter your answer, in simplified form, in the box.
lesya692 [45]
-2.5x is the answer for this question i believe if i did it right'<span />
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3 years ago
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aev [14]

Answer:

precipitation then condensation

Step-by-step explanation:

3 0
3 years ago
Which of the following comparisons is correct?<br>-2 2<br>4&lt;−4<br>−6&lt; −5
zlopas [31]
<h3>Answer: Choice D)   -6 < -5</h3>

================================================

Explanation:

Let's go through the answer choices

  • A) This is false because -2 is actually larger than -5. Make a number line and you'll see that -2 is to the right of -5. Numbers on the right are larger than numbers on the left.
  • B) This is also false. The value 0 is smaller than 2. A number line might help show this.
  • C) Also false. It should be 4 > -4. Any positive number is always larger than any negative number.
  • D) This is true. On a number line, -6 is to the left of -5, so -6 is smaller than -5. This makes -6 < -5 a true statement.

4 0
4 years ago
Ron's piano lesson starts in 2 hours. It takes him 30 minutes to get to the lesson. He has
RideAnS [48]

Answer:

2 hours=120 mins

120-(45+25)

120-(70)

50

Ron has enough time to finish his homework and walk the dog before his lesson. Ron should overestimate the total time needed. Since Ron has 50 minutes to spare he could add 25 to home work time and another 25 to walking his dog. he still ha time to do both.

4 0
3 years ago
Assume that a simple random sample has been selected from a normally distributed population. State the hypotheses, find the test
BaLLatris [955]

Solution

Hypotheses:

- The population mean is 132. In order to test the claim that the mean is 132, we should check for if the mean is not 132.

- Thus, the Hypotheses are:

\begin{gathered} H_0:\mu=132 \\ H_1:\mu\ne132 \end{gathered}

Test statistic:

- The test statistic has to be a t-statistic because the sample size (n) is less than 30.

- The formula for finding the t-statistic is:

\begin{gathered} t=\frac{\bar{X}-\mu}{\frac{s}{\sqrt{n}}} \\  \\ where, \\ \bar{X}=\text{ Sample mean} \\ \mu=\text{ Population mean} \\ s=\text{ Standard deviation} \\ n=\text{ Sample size} \end{gathered}

- Applying the formula, we have:

\begin{gathered} t=\frac{137-132}{\frac{14.2}{\sqrt{20}}} \\  \\ t=\frac{5}{3.1752} \\  \\ t\approx1.5747 \end{gathered}

Critical value:

- The critical value t-critical, is gotten by reading off the t-distribution table.

- For this, we need the degrees of freedom (df) which is gotten by the formula:

\begin{gathered} df=n-1 \\ df=20-1=19 \end{gathered}

- And then we also use the significance level of 0.1 and the fact that it is a two-tailed test to trace out the t-critical. (Note: significance level of 0.1 implies 10% significance level)

- This is done below:

- The critical value is 1.729

P-value:

- To find the p-value, we simply check the table for where the t-statistic falls.

- The t-statistic given is 1.5747. We simply check which values this falls between in the t-distribution table. It falls between 1.328 and 1.729. We can simply choose a value between 0.1 and 0.05 and multiply the result by 2 since it is a two-tailed test.

- However, we can also use a t-distribution calculator, we have:

- Thus, the p-value is 0.13183

Final Conclusion:

- The p-value is 0.13183, and comparing this to the significance level of 0.1, we can see that 0.13183 is outside the rejection region.

- Thus, the result is not significant and we fail to reject the null hypothesis

7 0
2 years ago
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