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3 years ago

Please help im confused :(

Mathematics

1 answer:

aev [14]3 years ago

3 0

Answer:

precipitation then condensation

Step-by-step explanation:

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13. A high school has 1600 students. In a random sample of 50 students, 15

Orlov [11]

Answer:

480

Step-by-step explanation:

In 50 student's play station is owned by =15 student's

∴ In 1 student play station is owned by =15÷50 student

∴In 1600 student's play station is owned by =(1600×15)÷50 student's

=480 student's

∴The number of the student at the high school who

own a Play station is 480

(Ans)

3 0

3 years ago

PLEASE HELP! What is the slope of the line that passes through the points below? (Enter your answer as a decimal if necessary.)

lozanna [386]

is the right answer.

because rise is 1 and run is 1 = 1/1 = 1

8 0

3 years ago

At what point does the curve have maximum curvature? Y = 4ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as

MAXImum [283]

<u>Answer-</u>

At $x= \frac{1}{2304e^4-16e^2}$ the curve has maximum curvature.

<u>Solution-</u>

The formula for curvature =

$K(x)=\frac{{y}''}{(1+({y}')^2)^{\frac{3}{2}}}$

Here,

$y=4e^{x}$

Then,

${y}' = 4e^{x} \ and \ {y}''=4e^{x}$

Putting the values,

$K(x)=\frac{{4e^{x}}}{(1+(4e^{x})^2)^{\frac{3}{2}}} = \frac{{4e^{x}}}{(1+16e^{2x})^{\frac{3}{2}}}$

Now, in order to get the max curvature value, we have to calculate the first derivative of this function and then to get where its value is max, we have to equate it to 0.

${k}'(x) = \frac{(1+16e^{2x})^{\frac{3}{2} } (4e^{x})-(4e^{x})(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})}{(1+16e^{2x} )^{2}}$

Now, equating this to 0

$(1+16e^{2x})^{\frac{3}{2} } (4e^{x})-(4e^{x})(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x}) =0$

$\Rightarrow (1+16e^{2x})^{\frac{3}{2}}-(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})$

$\Rightarrow (1+16e^{2x})^{\frac{3}{2}}=(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})$

$\Rightarrow (1+16e^{2x})^{\frac{1}{2}}=48e^{2x}$

$\Rightarrow (1+16e^{2x})}=48^2e^{2x}=2304e^{2x}$

$\Rightarrow 2304e^{2x}-16e^{2x}-1=0$

Solving this eq,

we get $x= \frac{1}{2304e^4-16e^2}$

∴ At $x= \frac{1}{2304e^4-16e^2}$ the curvature is maximum.

6 0

3 years ago

1,8,27; 64; Rule Missing numbers

zubka84 [21]

Answer:

rule: f(n) = n³

missing numbers: 125, 216, 343, 512, 729

Step-by-step explanation:

Your familiarity with the cubes of small integers helps you recognize each of these numbers is a cube. Their sequence is the sequence of cubes of increasing natural numbers.

1 = 1·1·1 = 1³

8 = 2·2·2 = 2³

27 = 3·3·3 = 3³

64 = 4·4·4 = 4³

The rule is ...

f(n) = n³

The cubes of 5 through 9 will complete the set of numbers ...

1, 8, 27, 64, 125, 216, 343, 512, 729

7 0

2 years ago

What's number 2 and 3

gtnhenbr [62]

El numero 2 eso seria

7 0

3 years ago