Complete question:
A circle with radius 3 has a sector with a central angle of 1/9 pi radians
what is the area of the sector?
Answer:
The area of the sector = 
square units
Step-by-step explanation:
To find the area of the sector of a circle, let's use the formula:
Where, A = area
r = radius = 3
Substituting values in the formula, we have:
The area of the sector = square units
Answer:
3x -2y = -5
Step-by-step explanation:
Standard form is ...
ax +by = c
where the leading coefficient (a, or b if a=0) is positive and a, b, c are mutually prime.
Multiplying the equation by 2 gives ...
2y = 3x +5
We can subtract 2y+5 to get standard form:
3x -2y = -5
First we need to find the slope of the function
The slope of a function is equal to
So now we plug this into the equation and find the slope (M will represent the slope)
So the slope is -3/2
Now we can use point-slope form.
Point slope form is represented by
So when we plug in our values we get
So the equation is
Y = -3/2X-7/2
9/16 ways to go...unless the gate is closer you didn't really say where the gate is
