To solve this problem it is necessary to apply the concept related to the definition of Density. Density is defined as the relationship between volume and mass. The greater the volume with respect to the mass, the smaller the mass tends to be and vice versa. By definition it is given by the formula:
Where,
V= Volume
m = Mass
From the data given we have to,
1g of the alloy will contain 0.61g Cu, 0.335g Zn and 0.05g Pb
Therefore if we calculate the volume of each element we have,
The density of the alloy would be
Therefore the density of the alloy is 
Answer: 35*10^3 N/m
Explanation: In order to explain this problem we know that the potential energy for spring is given by:
Up=1/2*k*x^2 where k is the spring constant and x is the streching or compresion position from the equilibrium point for the spring.
We also know that with additional streching of 2 cm of teh spring, the potential energy is 18J. Then it applied another additional streching of 2 cm and the energy is 25J.
Then the difference of energy for both cases is 7 J so:
ΔUp= 1/2*k* (0.02)^2 then
k=2*7/(0.02)^2=35000 N/m
Answer:
5.99×10⁶ m/s
Explanation:
We look for the speed of the electron by applying,
F = Bqv.................. Equation 1
Where F = Force on the electron, B = magnetic field, q = charge of an electron, v = speed of the electron.
make v the subject of the equation
v = F/Bq.............. Equation 2
Given: F = 2.4×10⁻¹² N, B = 2.5 T.
Constant: q = 1.602×10⁻¹⁹ C
Substitute into equation 2
v = 2.4×10⁻¹² /(2.5× 1.602×10⁻¹⁹ )
v = 5.99×10⁶ m/s
It doesn't make much difference where the stamp is placed.
