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7nadin3 [17]
3 years ago
14

Consider a particle launched at a horizontal velocity v0 from a height h above the ground. 1. Derive an expression for the time

it takes the projectile to strike the ground. Ignore air resistance.
Physics
1 answer:
Rina8888 [55]3 years ago
5 0

Answer:  t=\sqrt{\frac{2h}{g} }

Explanation: The time taken by the object to reach the ground depends up on the vertical velocity of the object.

The object horizontal velocity component only moves the object in forward direction and does not have any effect vertically

as the object is launched horizontally its initial vertical velocity is zero

u_y=0

the object experiences downward fall due to gravitational acceleration only since there is no air resistance

therefore a=g

the distance covered =s=h

now the kinematic equation could be used

h=u_yt+0.5at^2\\h=0+0.5gt^2\\h=\frac{gt^2}{2}\\t^2=\frac{2h}{g} \\t=\sqrt{\frac{2h}{g} }  

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A ray of light traveling in air strikes the surface of a liquid. if the angle of incidence is 29.7◦ and the angle of refraction
lana66690 [7]
When light moves from a medium with higher refractive index to a medium with lower refractive index, the critical angle is the angle above which there is no refracted ray, and it is given by:
\theta_c = \arcsin ( \frac{n_r}{n_i} ) (2)
where n_r is the refractive index of the second medium and n_i is the refractive index of the first medium.

We can find the ratio n_r / n_i by using Snell's law:
n_i \sin \theta_i = n_r \sin \theta_r (1)
where
\theta_i is the angle of incidence
\theta_r is the angle of refraction

By using the data of the problem and re-arranging (1), we find
\frac{n_r}{n_i} =  \frac{\sin \theta_i}{\sin \theta_r} = \frac{\sin 16.3^{\circ}}{\sin 29.7^{\circ}} =0.566

and if we use eq.(2) we can now find the value of the critical angle:
\theta_c = \arcsin ( \frac{n_r}{n_i} ) = \arcsin (0.566) = 34.5^{\circ}
3 0
3 years ago
A pilot flies in a straight path for 1 hour 30 minutes. She then makes a course correction, heading 45 degrees to the right of h
mrs_skeptik [129]

Answer:

1199 miles

Explanation:

1 hour 30 minutes = 1 + 30/60 = 1.5 hours

2 hours 15 minutes = 2 + 15/60 = 2.25 hours

The distance she flew in the 1st segment is:

1.5*345 = 517.5 miles

The distance she flew in the 2nd segment is:

2.25 * 345 = 776.25 miles

Since the 2nd segment is 45 degree with respect to the 1st segment, this means that she has flown

776.25 * cos(45) = 549 miles in-line with the 1st segment and

776.25* sin(45) = 549 miles perpendicular to the 1st segment:

So the distance from the end to her starting position is

\sqrt{(517.5 + 549)^2 + 549^2} = 1199 miles

4 0
3 years ago
Which vector goes from (-1, -3) to (-4, -1)
Alisiya [41]
Its this (couldn’t write it down on here properly so i had to ss it)
Basically, it’s just the difference between the x values at the top and the difference between the Y values at the bottom.

6 0
2 years ago
If you started the motor of a boat in the middle of a lake, who would detect the sound of the motor first: a friend sitting on t
ArbitrLikvidat [17]

Answer:

A friend snorkeling just below the surface of the water along the same shore will detect the sound first.

Explanation:

  • The speed of sound in water medium is faster than that through the air.
  • Sound propagates through the medium by transferring through the molecules on it. Water has more closely packed molecules due to which the speed is faster.
  • In fact, the sound's speed in water is almost four times faster than that in the air.
  • So the guy in the water surface gets to hear sound faster than the one in sore.
6 0
3 years ago
Read 2 more answers
A baseball thrown by a pitcher is hit by a batter. At the moment when the ball hits the bat, the force exerted on the bat by the
Slav-nsk [51]

Newton's Laws of motion describe the motion of an object based on the applied force

The correct option that gives the relationships between the forces is the the option;

\underline{F_{ball}}<u> on bat</u> = \underline{F_{bat}}<u> on ball</u>

<em>(Either option A or B without the minus symbol before </em>F_{bat}<em>, likely typographical error)</em>

<em />

Reason:

Force exerted on the bat by the ball = F_{ball}

Force exerted on the ball by the bat = F_{bat}

Given that the batter hits the ball with the bat, the force exerted by the bat on the ball, F_{bat}, is reacted to by the force of the ball acting on the bat, F_{ball}

According to Newton's third law of motion, action and reaction are equal and opposite. Therefore, at the moment when the ball hits the bat, we have;

\underline{F_{ball}}<u> on bat</u> = \underline{F_{bat}}<u> on ball</u>

<em>Where the force of the bat is high, the ball is accelerated to travel at high speed</em>

Learn more Newton's Laws of motion here:

brainly.com/question/24522313

8 0
2 years ago
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