4
Explanation:
The number 4 in the hydrologic cycle depicts surface runoff.
The hydrologic cycle depicts the cyclic movement of water between different earth components.
It shows water in all its phases.
- From the attached image, runoff is depicted 4.
- Runoff is water that moves on the surface after precipitation.
- Number 1 is evaporation where water changes to vapor.
- Number 2 is condensation where the vapor cools back to liquid.
- Number 3 is precipitation where the liquid water is forced down under gravity.
- On the surface, the water runs as runoff.
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Biogeochemical cycle brainly.com/question/3509510
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Molality is obtained by dividing the number of moles of solute by the mass in kilogram of the solvent. None of the dimensions is dependent in temperature. On the other hand, molarity is obtained by dividing the number of moles of solute by the volume in liters of the solution. Volume is temperature dependent.
1 gram = 1000 milligrams
/ move the decimal to the left 3 because you multiply by 10^3
5.712 grams = 5,712 milligrams
1 gram = 0.001 kilograms
/ move decimal to the right 3 because you multiply by 10^ -3
5.712 grams = 0.005712 kilograms
Answer:
Volume of gold is 9.64 L
.
Explanation:
Given data:
Mass of gold = 85 g
Temperature = standard = 273 K
Pressure = standard = 1 atm
Volume of gold = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will calculate the number of moles of gold.
Number of moles = mass/molar mass
Number of moles = 85 g/ 197 g/mol
Number of moles = 0.43
1 atm × V = 0.43 mol ×0.0821 atm.L/ mol.K × 273 K
V = 9.64 atm.L / 1 atm
V = 9.64 L
Answer : The integer 'x' in the hydrate is, 2
Explanation : Given,
Mass of hydrate = 4.31 g
Mass of anhydrous = 3.22 g
First we have to calculate the mass of water.
Mass of water = Mass of hydrate - Mass of anhydrous
Mass of water = 4.31 g - 3.22 g
Mass of water = 1.09 g
Now we have to calculate the moles of and
Molar mass of = 18 g/mol
and,
Molar mass of = 106 g/mol
Now we have to calculate the ratio of and
The formula of compound is,
The value of 'x' is, 2
So, the formula of compound is,
Thus, the integer 'x' in the hydrate is, 2