To determine the amount of a certain element in a compound, we use the ratio of the elements from the compound. We calculate is follows:
45.0 g CCl4 ( 1 mol CCl4 / 153.82 g CCl4 ) ( 1 mol C / 1 mol CCl4 ) ( 12.01 g C / 1 mol C ) = 3.5135 g carbon present
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Answer:
Explanation:
https://www.bbc.co.uk/bitesize/guides/zxgkp39/revision/3
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Answer:
yo gotta be more specific
Answer:
the correct answer is D. Both energy and mass can enter or exit a closed system.
Explanation:
