The volume is 12 mL (0.012 L)
Before the aluminum was added, the water reached 132mL. After it was added, it reached 144. That means the Aluminum takes up (144-132)= 12mL of space.
The density = mass/volume. If the aluminum bar has a mass of 78g and volume of 0.012L, 78/0.012=6,500 g/L
Answer:
halogen
Explanation:
Group VIIA/halogen/ is the only group in periodic table in which all the elements are nonmetals. This group contains F, Cl, Br, I, and At. <em>Halogen</em> meaning salt producer.
Answer:
(a) When aqueous solution of hydrochloric and ammonia chemically react together then it results in the formation of ammonium chloride.
The reaction equation for this reaction is as follows.
Now, ioni equation for this reaction is as follows.
Cancelling the spectator ions, the net ionic reaction equation is as follows.
(b) When sodium hydroxide chemically reacts with ammonium chloride then it forms ammonia, water and sodium chloride as follows.
Now, the total ionic equation will be as follows.
Cancelling the spectator ions from the above equation. Then the net ionic equation will be as follows.
Answer:
BaSO₄
Explanation:
Let's assume we have 100 g of the compound. If that's the case we would have:
Now we <u>convert the masses of each element into moles</u>, using their <em>respective molar masses</em>:
- 58.8 g Ba ÷ 137.327 g/mol = 0.428 mol Ba
- 13.74 g S ÷ 32 g/mol = 0.429 mol S
- 27.43 g O ÷ 16 g/mol = 1.71 mol O
We <u>divide those moles by the lowest number among them</u>:
We can express those results as Ba₁S₁O₄, meaning the empirical formula is thus BaSO₄.
The mass of a nickel coin is 5 g.
1 mol of Ni weighs 58 g. 1 mol contains 6.022 x 10²³ atoms of Ni.
therefore in 58 g there are 6.022 x 10²³ atoms of Ni
then in 5 g the number of Ni atoms are - 6.022 x 10²³ /58 x 5 = 5.2 x 10²² Ni atoms
Therefore number of Ni atoms are 5.2 x 10²² atoms in a nickel coin
