All categories

3 years ago

Scientists usually write reports about their investigations. Why do they do this?

1 answer:

5 0

As for me, the reson why scientists usually write reports about their investigations is because they want to <span>d. to communicate their work to other scientist. As far as I am concerned in this sphere they have to get many other opnions besides their own in order to complete or expand one that they have made up. Hope it helps :)</span>

You might be interested in

In Case 1, a mass M hangs from a vertical spring having spring constant k and is at rest in its equilibrium position. In Case 2

evablogger [386]

Answer: hello your question is incomplete attached below is the complete question

answer : 1/2 KD^2 ( option A )

Explanation:

P.E ( potential energy ) = mgd

In case 1 P.E = 0 i.e. mgd = 0

Given that in case 2 the Mass M had moved through the Distance D by the compression of the spring

<u>The potential energy of the M in case 2 </u>

= P.E of M at rest + P.E of the spring

= 0 + 1/2 KD^2

4 0

3 years ago

What does the slope of the curve on a distance vs time graph represent?

Lilit [14]

Slope of a curve Y plotted against X is mathematically given as

$slope = \frac{dy}{dx}$

now here we can see that if similarly graph is plotted against distance and time then slope is given as

$slope = \frac{dx}{dt}$

here we can say that above is ratio of small distance and very small interval of time.

so here we can say that this ratio of distance and time for very small interval of time is known as instantaneous speed of the object which is falling freely under gravity.

So here slope of the graph will represent the speed at a given instant.

6 0

3 years ago

8. An unpowered flywheel is slowed by a constant frictional torque. At time t = 0 it has an angular velocity of 200 rad/s. Ten s

allsm [11]

Answer:

a) $\omega = 50\,\frac{rad}{s}$ , b) $\omega = 0\,\frac{rad}{s}$

Explanation:

The magnitude of torque is a form of moment, that is, a product of force and lever arm (distance), and force is the product of mass and acceleration for rotating systems with constant mass. That is:

$\tau = F \cdot r$

$\tau = m\cdot a \cdot r$

$\tau = m \cdot \alpha \cdot r^{2}$

Where $\alpha$ is the angular acceleration, which is constant as torque is constant. Angular deceleration experimented by the unpowered flywheel is:

$\alpha = \frac{170\,\frac{rad}{s} - 200\,\frac{rad}{s} }{10\,s}$

$\alpha = -3\,\frac{rad}{s^{2}}$

Now, angular velocities of the unpowered flywheel at 50 seconds and 100 seconds are, respectively:

a) t = 50 s.

$\omega = 200\,\frac{rad}{s} - \left(3\,\frac{rad}{s^{2}} \right) \cdot (50\,s)$

$\omega = 50\,\frac{rad}{s}$

b) t = 100 s.

Given that friction is of reactive nature. Frictional torque works on the unpowered flywheel until angular velocity is reduced to zero, whose instant is:

$t = \frac{0\,\frac{rad}{s}-200\,\frac{rad}{s} }{\left(-3\,\frac{rad}{s^{2}} \right)}$