Answer:
Beryllium bromide
Explanation:
There exists 2 elements in the question
Beryllium Be with valence of +2, and it's a metal
Bromine Br with a valence of -1, and is a non - metal.
Both of them combine together forming an ionic bond:
Be + Br(2) -> BeBr(2)
In naming the compound, we would say that since the first is a metal, beryllium, and the second being a halogen, bromine. We name it by calling the first name together with the last name and changing the last name of the non metal from -ine to -ide.
So we have, Beryllium Bromide.
Answer:
Explanation:
This question appears incomplete because of the absence of the data been talked about in the question. However, there is a general ruling here and it can be applied to the data at hand.
If an increase in the distance of charges (let's denote with "d") causes the electric field strength (let's denote with"E") to increase, then the mathematical representation can be illustrated as d ∝ E (meaning distance of charge is directly proportional to electric field strength).
But if an increase in the distance of the charges causes the electric field strength to decrease, then the mathematical representation can be illustrated as d ∝ 1/E (meaning distance of charge is inversely proportional to electric field strength).
A scatterplot can also be used to determine this. If there is a positive correlation (correlation value is greater than zero but less than or equal to 1) on the graph, then it is illustrated as "d ∝ E" BUT if there is a negative correlation (correlation value is less than zero but greater than or equal to -1), then it can be illustrated as "d ∝ 1/E".
