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xenn [34]
3 years ago
12

two metal plates are near each other. explain why they will not become charged until connected to a souce of potential differenc

e
Physics
1 answer:
scZoUnD [109]3 years ago
7 0

Answer:

idk

Explanation:

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An octopus propels itself through the water by ejecting water through a funnel in its body. How does this demonstrate Newton’s t
valina [46]

Answer: The answer would be C. When Octopus eject the water out, the water acts with an equal force on the octopus in opposite direction.

Explanation:

An octopus propels itself forward in the water by ejecting water backward through a funnel in its body.

Hope this helps! :D

8 0
3 years ago
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oil is flowing through a tube that has two different cross-sectional areas. at position a where the radius of the tube is 7.0 cm
AleksAgata [21]

According to the continuity equation, the rate at which mass enters the system equals the rate at which mass exits in any steady state process.

An equation that explains the movement of a particular quantity is a continuity equation, also known as a transport equation. Although it can be applied generally to any significant quantity, it is extremely simple and useful when used with preserved quantities.

The radius is seven centimeters, and the mass flow rate is 0 to 5 kg/s. Find the mass flow rate at a point with a 3.5 cm radius. We can consequently deduce that based on the equation. As we all know, the mass flow rate is constant.

If the rate of mass entering and leaving the system is equal, the rate of mass leaving the system should be processed.

The mass flow rate air section A and the mass flow rated section B are equivalent, according to the continuity equation. Mass flow rate in section B is therefore 0.02, or five kilograms per second.

To know more about continuity equation, click on the link below:

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5 0
1 year ago
A ball is tossed from an upper-story window of a building. the ball is given an initial velocity of 8.00 m/s at an angle of 20.0
otez555 [7]
A) The motion of the ball consists of two indipendent motions on the horizontal (x) and vertical (y) axis. The laws of motion in the two directions are:
x(t)=v_0 \cos \alpha t
y(t)=h-v_0 \sin \alpha t - \frac{1}{2}gt^2
where
- the horizontal motion is a uniform motion, with constant speed v_0 \cos \alpha, where v_0 = 8.00 m/s and \alpha=20.0^{\circ}
- the vertical motion is an uniformly accelerated motion, with constant acceleration g=9.81 m/s^2, initial position h (the height of the building) and initial vertical velocity v_0 \sin \alpha (with a negative sign, since it points downwards)

The ball strikes the ground after a time t=3.00 s, so we can find the distance covered horizontally by the ball by substituting t=3.00 s into the equation of x(t):
x(3.00 s)=v_0 \cos \alpha t=(8 m/s)(\cos 20^{\circ})(3.0 s)=22.6 m

b) To find the height from which the ball was thrown, h, we must substitute t=3.00 s into the equation of y(t), and requiring that y(3.00 s)=0 (in fact, after 3 seconds the ball reaches the ground, so its vertical position y(t) is zero). Therefore, we have:
0=h-v_0 \sin \alpha t -  \frac{1}{2}gt^2
which becomes
h=(8 m/s)(\sin 20^{\circ})(3.0 s)+ \frac{1}{2}(9.81 m/s^2)(3.0 s)^2=52.3 m

c) We want the ball to reach a point 10.0 meters below the level of launching, so we want to find the time t such that 
y(t)=h-10
If we substitute this into the equation of y(t), we have
h-10 = h-v_0 \sin \alpha t-  \frac{1}{2}gt^2
\frac{1}{2}gt^2+v_0 \sin \alpha t -10 =0
4.9 t^2 +2.74 t-10 =0
whose solution is t=1.18 s (the other solution is negative, so it has no physical meaning). Therefore, the ball reaches a point 10 meters below the level of launching after 1.18 s.

4 0
4 years ago
Food deteriorated more slowly in a refrigerator because
REY [17]
Because the low temperature in the refrigerator slows the action of bacteria and fungi on food substances.
6 0
3 years ago
Calculate the force between two touching grape fruits each with a radius of 0.08 meters and a mass of 0.45 kilograms
Volgvan
Hope it cleared your doubt.

3 0
3 years ago
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