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Anit [1.1K]
3 years ago
15

consider a packed bed of 10cm diameter concrte (stone mix) spheres to be used as a thermal (energy) storage sysytem initailly th

e speheres are 15 deg C; airat 50deg C flows around each sphere providing a convection coefficeint of 10Wm^-2k^-1. What will be surface temperature of these spheres after 5 hours
Engineering
1 answer:
hodyreva [135]3 years ago
8 0

Answer: ok bit sp are 16 degrees

Explanation:

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The viscosity of the water was 2.3×10^−5lb⋅⋅s/ft^2 and the water density was 1.94 slugs/ft^3. Estimate the drag on an 88-ft diam
Lina20 [59]

Answer:

hello your question is incomplete attached below is the complete question

answer : Drag force = 1.3 Ib

Explanation:

we have to represent the dimensions of the drag force in terms of FLT

i.e : D = f( <em>d,v,p,u </em>) represented in terms of FLT

D = F , V = LT^-1,  d = L, p = FL^-4 T^2

u = FL^-2 T,  Number of independent terms = 5

attached below is the detailed solution

6 0
4 years ago
Which of the following is used as part of a four-wheel drive system? A. Front drive axles B. Transfer Case C. Front Drive Shaft
xxMikexx [17]

Answer:

D: All of the above.

Have a good day!

4 0
4 years ago
Parity Detect of Three Inputs 20 pts. (EVEN) a) Draw a function table showing the three data lines and the output function F. 4
DIA [1.3K]

Answer:

See attached picture.

Explanation:

4 0
3 years ago
You push a 10 n object 10 m how much work was done on the object​
dezoksy [38]

Answer: the answer is

Work= Force * Distance

Work= 10N * 10m

Work= 100J

Explanation:

5 0
3 years ago
Read 2 more answers
An insulated 40 ft^3 rigid tank contains air at 50 psia and 580°R. A valve connected to the tank is now opened, and air is allow
Pachacha [2.7K]

Answer:

The answer is "\bold{W_{in} = 645.434573 \ Btu}".

Explanation:

Its air enthalpy is obtained only at a given temperature by A-17E.  

The solution from the carbon cycle is acquired:

\to \Delta U= W_{in}-m_{out}h_{out}=0\\\\\to W_{in} = (m_1 - m_2)h

           =\frac{Vh}{RT}(P_1- P_2)\\\\= \frac{40 \times 138.66}{0.3704\times 580}(50-25) Btu\\\\= \frac{5,546.4}{214.832}(25) Btu\\\\= 25.8173829(25) Btu\\\\ =645.434573 Btu

W_{in} = 645.434573 \ Btu

8 0
3 years ago
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