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Kisachek [45]
3 years ago
8

Question: In experiment your teacher has provided you with a sample of sandy, salty, ocean water and

Chemistry
1 answer:
liq [111]3 years ago
3 0

Answer:

Explanation:

Homogeneous mixture is a mixture in which the components of the mixture are in the same proportion throughout any sample extracted from the mixture while an heterogeneous mixture is a mixture in which the components of the mixture differ in term of proportion when different samples of the mixture are extracted and compared.

For example, a sandy water will have some parts (usually the bottom) of the mixture with more sand than other parts of the mixture, hence, it (sandy water) is a heterogeneous mixture. While salty and ocean water has it's salt dissolved in the same proportion throughout the water in the mixture, hence salty and/or ocean water is a homogeneous mixture.

Sandy water can be separated by filtration (i.e using a filter paper to separate the sand from the water when the mixture is poured over a filter paper) while salty and ocean water can be separated by distillation (i.e boiling of the mixture so the water molecules can boil and move through a tube as gas or steam into another container where they are cooled and converted back to liquid or water while leaving the solid salt component of the mixture in the boiling tube).

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How much (mL) of a 2.0 M sodium hydroxide solution would it take to neutralize 50 mL of a 6.0 M solution of hydrochloric acid?
Tom [10]

Answer:

150ml

Explanation:

For this question,

NaOH completely dissociates. It is a strong base

HCl also completely dissociates. It is a strong acid

So we have this equation

m1v1 = m2v2 ----> equation 1

M2 = 2m

V1= ??

M2 = 6m

V2 = 50m

When we input these into equation 1, we have:

2m x v1 = 6m x 50ml

V1 = 6m x 50ml/2

V1 = 300/2

V1 = 150ml

Therefore NaOH that is required to neutralize the solution of hydrochloric acid is 150ml.

Thank you

8 0
2 years ago
Los hermanos Ana Victoria y José Leonardo están patinando en el hielo, con 25 y 20 kg respectivamente de masa, si Victoria empuj
andreyandreev [35.5K]

Utiliando las leyes de Newton encontraremos que la aceleración de Ana es -1.6 m/s^2.

La segunda ley de Newton dice que:

F = m*a

Fuerza es igual a masa por aceleración.

La tercera ley de Newton dice que cuando dos objetos interactuan, cadan objeto ejerce una fuerza de <u>igual magnitud pero opuesta direccion</u> en el otro.

Ahora veamos como aplicar esto.

Sabemos que la niña empuja al niño, asumamos que con una fuerza F.

Tendremos entonces la ecuación:

F = 20kg*(2m/s^2) = 40N

Y por la tercer ley de Newton, esta misma fuerza (pero en opuesta dirección) se aplica a la niña, entonces tendremos:

-40N = 25kg*a

-40N/25kg = a = -1.6 m/s²

La aceleración con la que retrosede la niña es -1.6 m/s²

Sí quieres aprender más, puedes leer:

brainly.com/question/17123407

3 0
3 years ago
Calculate the standard enthalpy change for the reaction at 25 ∘ C. Standard enthalpy of formation values can be found in this li
meriva

Answer:

The standard enthalpy change for the reaction at 25^{0}\textrm{C} is -2043.999kJ

Explanation:

Standard enthalpy change (\Delta H_{rxn}^{0}) for the given reaction is expressed as:

\Delta H_{rxn}^{0}=[3mol\times \Delta H_{f}^{0}(CO_{2})_{g}]+[4mol\times \Delta H_{f}^{0}(H_{2}O)_{g}]-[1mol\times \Delta H_{f}^{0}(C_{3}H_{8})_{g}]-[5mol\times \Delta H_{f}^{0}(O_{2})_{g}]

Where \Delta H_{f}^{0} refers standard enthalpy of formation

Plug in all the given values from literature in the above equation:

\Delta H_{rxn}^{0}=[3mol\times (-393.509kJ/mol)]+[4mol\times (-241.818kJ/mol)]-[1mol\times (-103.8kJ/mol)]-[5mol\times (0kJ/mol)]=-2043.999kJ

4 0
3 years ago
How many moles in 58 grams of CO3 ?
Romashka [77]

Answer:

60.0089

Explanation:

7 0
2 years ago
Blue litmus paper turn red in a basic solution. correct/incorrect<br>​
kherson [118]

Answer:

correct

Explanation:

please follow me

4 0
3 years ago
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