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Simora [160]
4 years ago
10

Which conclusion could be made from Ernest Rutherford’s gold foil experiment?

Chemistry
2 answers:
Tamiku [17]4 years ago
8 0
The nucleus while large has a small ratio of mass when dealing with atoms, they are very spread out and are mostly solid with a blocky shape.
Dmitriy789 [7]4 years ago
5 0

Answer:

The correct option is :Atoms are made up of mostly empty space.

Explanation:

Ernest Rutherford’s gold foil experiment has following observation:

  • Most of the alpha particles had easily escaped through the atom which accounts for that atom is mostly empty space.
  • Very less number of alpha particles were deflected from their path which indicated that positive charge is only concentrated in the center of the atom which termed as nucleus of an atom where positively charged i.e protons are located.
  • Whole the mass of an atom is concentrated in the nucleus of the atom.
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astraxan [27]

Answer:

Explanation:The equation for this is F = -GmM/R^2 where the minus sign says the force is attractive m is 10 kg, M is 20 kg and R is 5 meters. If you crunch the numbers you get an answer of:

7 0
3 years ago
What is the pressure of 2.50 moles of an ideal gas if it has a volume of 50.0 liters when the temperature is 300.0 K
Ierofanga [76]
Start with the ideal gas equation, <span><span><span>PV=nRT</span> </span><span>PV=nRT</span></span> and rearrange for pressure to get <span><span><span>p=<span><span>nRT</span>V </span></span> </span><span>p=<span><span>nRT</span>V</span></span></span> . You have all the necessary variables in their proper units, so plug em' into the equation to solve for pressure in units of atmospheres.

<span><span><span>P=<span><span>(2.5 mol)(300 K)(0.08206 L atm <span><span>K </span><span><span>−1</span> </span></span> mo<span><span>l </span><span><span>−1</span> </span></span></span><span>50.0 L</span> </span>=1.23 atm</span> </span><span>P=<span><span>(2.5 mol)(300 K)(0.08206 L atm <span>K<span>−1</span></span> mo<span>l<span>−1</span></span></span><span>50.0 L</span></span>=1.23 atm</span></span>

All that needs to be done now is converting atmospheres to mm <span><span><span>Hg</span> </span><span>Hg</span></span> .

<span><span><span>1.23 atm∗<span><span>760 mm Hg</span><span>1 atm</span> </span>=935 mm Hg</span> </span><span>1.23 atm∗<span><span>760 mm Hg</span><span>1 atm</span></span>=935 mm Hg</span></span> .

That value makes sense, since the original pressure in atmospheres was above 1, the pressure in mm <span><span><span>Hg</span> </span><span>Hg</span></span> will be above 760.
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3 years ago
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aleksandrvk [35]

Answer:

Can I get my 50 points now?

Explanation:

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