MO Diagram of C₂⁻ is shown below,
Bond order is calculated as,
Bond Order = [# of e⁻s in BMO]-[#of e⁻s in ABMO] / 2
Where,
BMO = Bonding Molecular Orbital
ABMO = Anti-Bonding Molecular Orbital
Putting values,
Bond Order = [9]-[4] / 2
Bond Order = 5 / 2
Bond Order = 2.5
Answer:
C₆H₁₂O₆ < NaCl ≈ CH₃OH < MgCl₂
Step-by-step explanation:
The formula for <em>osmotic pressure</em> (Π) is
Π = icRT
If T is constant,
Π = kic
<em>C₆H₁₂O₆:
</em>
Π = k × 1 × 1 = k
<em>MgCl₂:
</em>
Π = k × 3 × 1 = 3k
<em>CH₃OH:
</em>
Π = k × 1 × 2 = 2k
<em>NaCl:
</em>
Π = k × 2 × 1 = 2k
The order of osmotic pressures is
C₆H₁₂O₆ < NaCl ≈ CH₃OH < MgCl₂
Answer:
Mass of sample is 99.9 g, density of ample is 11.35 
and temperature of sample is 
Explanation:
Mass is an additive property. Therefore mass of combined sample is summation of masses of two pellets.
Mass of combined sample = (37.2+62.7) g = 99.9 g
Density is an intensive property. Therefore density of combined sample of lead will be same as with density of Pb.
Density of combined sample = 11.35
Temperature is an intensive property. Therefore temperature of combined sample of lead will be same as with individual pellets.
temperature of combined sample =
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