Answer:
1.67×10^-1
Explanation:
Use the formula n=m/R.M.M
Find the R.M.M. Formula of the compound is AgNO3.
So Ag mass is 108, N mass is 14, and O mass is 16.
So 108+14+(16×3)=170.
Than use formula n=28.39/170 giving 0.167. In scientific notation 1.67×10^-1.
I think
Answer: The initial partial pressures of and is 139.4 torr.
Explanation:
The equilibrium reaction is
initially conc. p p 0
At eqm. p-2x p-x 2x
Given:
The expression for equilibrium constant is :
= 2x =115 torr
= (p-2x) = p-115 torr
= (p-x)= p-57.5 torr
Now put all the given values in this expression, we get
Therefore, the initial partial pressures of and is 139.4 torr.
The independent variable is the thing you change and the dependent variable is the thing you measure
Please add you assignment.
Answer:
weight = mg
= 2 X 9.8 (g = 9.8m/s^2)
= 19.6 N is the correct answer