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Alex787 [66]
3 years ago
12

PLEASE FILL IN THE BLANKS IM DYING OMGGGGG

Chemistry
1 answer:
Sidana [21]3 years ago
5 0
Neutrons: +1
that's all

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The following pairs of soluble solutions can be mixed. In some cases, this leads to the formation of an insoluble precipitate. D
Westkost [7]

Answer:

a) K_{2} S and NH_{4} Cl :

There are no insoluble precipitate forms.

b) Ca Cl_{2} and (NH_{4} )_{2} Co_{3} :

There are the insoluble precipitates of CaCo_{3}  forms.

c) Li_{2}S and MnBr_{2} :

There are the insoluble precipitates of MnS  forms.

d) Ba(No_{3} )_{2} and Ag_{2} So_{4} :                        

As Ag_{2} So_{4} is insoluble, therefore no precipitate forms.

e) Rb_{2}Co_{3} and NaCl:

There are no insoluble precipitates forms.

Explanation:

a)

Solubility rule suggests:- K_{2} S ⇒ soluble, NH_{4} Cl ⇒ soluble.

                                          KCl ⇒ soluble, (NH_{4})_{2} S  ⇒ soluble.

There are no insoluble precipitate forms.

b)

Solubility rule suggests:- Ca Cl_{2} ⇒ soluble, (NH_{4} )_{2} Co_{3} ⇒ soluble.

                                        CaCo_{3} ⇒ insoluble, NH_{4} Cl  ⇒ soluble.

There are the insoluble precipitates of CaCo_{3}  forms.

c)

Solubility rule suggests:- Li_{2}S ⇒ soluble, MnBr_{2} ⇒ soluble.

                                        LiBr ⇒ soluble, MnS  ⇒ insoluble.

There are the insoluble precipitates of MnS  forms.

d)

Solubility rule suggests:- Ba(No_{3} )_{2} ⇒ soluble, Ag_{2} So_{4} ⇒insoluble.

                                     

As Ag_{2} So_{4} is insoluble, therefore no precipitate forms.

e)

Solubility rule suggests:- Rb_{2}Co_{3} ⇒ soluble, NaCl ⇒ soluble.

                                        RbCl ⇒ soluble, Na_{2} Co_{3}  ⇒ soluble.

There are no insoluble precipitates forms.

6 0
3 years ago
1. Swimming pool manufacturers recommend maintaining the
Viefleur [7K]

A 3.4 × 10⁶ L swimming pool must have a mass of 1.0 × 10⁷ mg Cl₂ to maintain a concentration of 3.0 ppm.

<h3>What is "ppm"?</h3>

"ppm" of "parts per million" is a unit of concentration equivalent to milligrams of solute per liters of solution.

A pool must maintain a chlorine concentration of 3.0 ppm (3.0 mg/L). The mass of chlorine in 3.4 × 10⁶ L is:

3.0 mg Cl₂/L × 3.4 × 10⁶ L = 1.0 × 10⁷ mg Cl₂

A 3.4 × 10⁶ L swimming pool must have a mass of 1.0 × 10⁷ mg Cl₂ to maintain a concentration of 3.0 ppm.

Learn more about ppm here: brainly.com/question/13395702

#SPJ1

4 0
2 years ago
How many neutrons are present in an atom of
Tamiku [17]
There’s going to be 8 neutrons presented
4 0
3 years ago
Consider the following reversible reaction.
andriy [413]

Answer:

No one is correct. The correct expression is:

Keq = [H₂]²  . [O₂]² / [H₂O]²

Explanation:

To build the Keq expression in a chemical equilibrium you must consider the molar concentrations of reactants / products, and they must be elevated to the stoichiometric coefficient.

The balance reaction is:

<u>2</u> H₂O (g)  ⇄  <u>2</u> H₂ (g)  +  O₂ (g)

Keq = [H₂]²  . [O₂]  / [H₂O]²

In opposite side: <u>2</u> H₂ (g)  +  O₂ (g)   ⇄  <u>2</u> H₂O (g)

Keq =  [H₂O]² / [H₂]²  . [O₂]  

6 0
4 years ago
Which of the following changes will decrease the rate of collisions between gaseous molecules oftype A and B in a closed contain
Leni [432]
D - take away B molecules
4 0
3 years ago
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