THE BALL'S ACCELERATION IS 130.90
Explanation:
According to Newton's second law "the force (F) acting on an object is equal to the mass (m) of an object times its acceleration (a)", meaning that when the soccer player kicks a ball, a force is acting on the ball, therefore increasing it's acceleration
SO FOR CALCULATING THIS WE WILL USE NEWTON LAW,
FORCE = MASS × ACCELERATION
WE ARE GIVEN
FORCE = 57.6N
MASS= .44KG
SO HERE WE APPLYING FORMULA ,WE WILL GET
ACCELERATION = 
ACCELERATION = 
ACCELERATION =130.90
Answer:
hello your question is incomplete attached below is the missing part
answer : short period oscillations frequency = 0.063 rad / sec
phugoid oscillations natural frequency (
) = 4.27 rad/sec
Explanation:
first we have to state the general form of the equation
= 
where :


comparing the general form with the given equation
= 18.2329

hence the short period oscillation frequency (
) = 0.063 rad/sec
phugoid oscillations natural frequency (
) = 4.27 rad/sec
1.A) 4.9 m
AL2006 Ace
The instant it was dropped, the ball had zero speed.
After falling for 1 second, its speed was 9.8 m/s straight down (gravity).
Its AVERAGE speed for that 1 second was (1/2) (0 + 9.8) = 4.9 m/s.
Falling for 1 second at an average speed of 4.9 m/s, is covered 4.9 meters.
ANYTHING you drop does that, if air resistance doesn't hold it back.
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2 idk sorry
If the lightbulb A in the circuit shown in the image burned out, the path for the current to flow is disrupted because one of its terminals is connected direct to the source. So, there will be no current through the lightbulbs B, C, and D, and they will turn off. Similarly it will happen, if the lightbulb D burned out.
If the lightbulb B burned out the current will continue circulating through the lightbulbs A, C, and D, because lightbulb B is connected in parallel. Similarly it will happen, if the lightbulb C burned out.