Help please asap!!!!!!!!!!!

If the perimeter of a square is 20, find the length of a diagonal

avanturin [10]

Answer:

7.07

Step-by-step explanation:

<h2><u>Length</u></h2>

a square has equal length on each side

hence is the perimeter is 20 it means that :

each side is 20/4 = 5

we can make a diagonal line which create 3 right angled triangles

2 sides of the triangle are 5 , this is the base and the height

to find the length we can make use of the Pythagoras theorem

c^2 = a^2 + b^2

c is the hypotenuse ( the diagonal;)

a and b are the opposite and adjacent

hence :

c^2 = 5 ^2 + 5^2

c^2 = 50

c = $\sqrt{50}$

c = 7.071

to 3sf

<h3><u>diagonal length = 7.07</u></h3>

6 0

3 years ago

Please Help!!! 30 Points

Alona [7]

Answer:

c lololololo

Step-by-step explanation:

8 0

3 years ago

April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3

vlada-n [284]

Answer:

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = $5\frac{1}{4}\ hrs$

$5\frac{1}{4}\ hrs$ can be Rewritten as $\frac{21}{4}\ hrs$

Number of Hours Carl worked on Math project = $\frac{21}{4}\ hrs$

Number of Hours Sonia worked on Math project = $6\frac{1}{2}\ hrs$

$6\frac{1}{2}\ hrs$ can be rewritten as $\frac{13}{2}\ hrs$

Number of Hours Sonia worked on Math project = $\frac{13}{2}\ hrs$

Number of Hours Tony worked on Math project = $5\frac{2}{3}\ hrs$

$5\frac{2}{3}\ hrs$ can be rewritten as $\frac{17}{3}\ hrs.$

Number of Hours Tony worked on Math project = $\frac{17}{3}\ hrs.$

Now Given:

April worked $1\frac{1}{2}$ times as long on her math project as did Carl.

$1\frac{1}{2}$ can be Rewritten as $\frac{3}{2}$

Number of Hours April worked on math project = $\frac{3}{2}$ $\times$ Number of Hours Carl worked on Math project

Number of Hours April worked on math project = $\frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs$

Also Given:

Debbie worked $1\frac{1}{4}$ times as long as Sonia.

$1\frac{1}{4}$ can be Rewritten as $\frac{5}{4}$ .

Number of Hours Debbie worked on math project = $\frac{5}{4}$ $\times$ Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = $\frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs$

Also Given:

Richard worked $1\frac{3}{8}$ times as long as tony.

$1\frac{3}{8}$ can be Rewritten as $\frac{11}{8}$

Number of Hours Richard worked on math project = $\frac{11}{8}$ $\times$ Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = $\frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs$

Hence We will match each student with number of hours she worked.

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

5 0

3 years ago

Read 2 more answers

The masses of the oranges on sale at a farm stand are normally distributed with a mean of 239 grams and a standard deviation of

ra1l [238]

Answer:

0.8

Step-by-step explanation:

i just took the test

8 0

3 years ago

What does 6•7-27•9+64=

Natali [406]

Hi!

$6*7-27*9+64$

$42-27*9+64$

$42-243+64$

$Answer---->=-137$

Explanation: <u><em>This question is super super easy to me. This question is about how to use their order of operations the math problems. First you had to used PEMDAS stands for P-Parenthesis first, E-Exponents second, M-Multiply third, D-Divide fourth, A-Add fifth, and S-Subtract sixth. Then multiply and divide from left to right with 6*7=42. Then 27*9=243,42-243+64, and add or subtract from left to right with 42-243+64=-137 is the right answer. Hope this helps! And thank you for posting your question at here on Brainly. And have a great day. -Charlie</em></u>

4 0

3 years ago