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Snowcat [4.5K]
3 years ago
6

What is the measure of A? And B

Mathematics
2 answers:
sladkih [1.3K]3 years ago
7 0

Answer:

A = 72°

B = 108°

Step-by-step explanation:

5y - 3 = 3y + 27

5y - 3y = 27 + 3

2y = 30

y = 30/2

y = 15

A = 5y - 3

A = 5(15) - 3

A = 75 - 3

A = 72°

A + B = 180°

72° + B = 180°

B = 180° - 72°

B = 108°

bekas [8.4K]3 years ago
6 0
A=72
B=108
That’s should be the answer
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AfilCa [17]

Answer:

a) The trains will be 1520 km apart at 2:40 pm for the cargo train and at 4:40 pm for the passenger train.

b) At that time the cargo train has traveled 560.04 km and the passenger train has traveled 960.12 km.

Step-by-step explanation:

a) First, we need to find the distance traveled by the cargo train in the two hours before the passenger train leaves Chicago:

x_{1} = v_{1}t_{1} = 120 km/h*2h = 240 km                    

Now, we can find the time when the trains will be 1520 km apart:

1520 km = (x_{1} + 240 km) + x_{2}      

Where 1 is for the cargo train and 2 is for the passenger train.

1520 km = (v_{1}*t_{1} + 240 km) + v_{2}t_{2}      

Since we need to calculate the time when the trains are 1520 km apart, t₁ = t₂, so:

1520 km = (v_{1}*t + 240 km) + v_{2}t              

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t_{1} = 12 pm + 2 h + 40 min = 2:40 pm

And for a passenger train, it will be 1520 km apart from the cargo train at:

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Hence, the trains will be 1520 km apart at 2:40 pm for the cargo train and at 4:40 pm for the passenger train.  

b) The distance traveled by both trains is given by:

x_{1} = v_{1}*t + 240 km = 120 km/h*2.667 h + 240 km = 560.04 km    

x_{2} = v_{2}*t = 360 km/h*2.667 h = 960.12 km    

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I hope it helps you!        

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Step-by-step explanation:

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