Here in order to find out the distance between two planes after 3 hours can be calculated by the concept of relative velocity
here
speed of first plane is 700 mi/h at 31.3 degree
speed of second plane is 570 mi/h at 134 degree
now the relative velocity is given as
now the distance between them is given as
so the magnitude of the distance is given as
miles
so the distance between them is 2985.6 miles
Answer:
Relative to Sir George's starting point, the knights collide at a distance of 38.43 m from Sir George's starting point.
Explanation:
Let the distance covered by Sir George be
and the distance covered by Sir Alfred be
Since the knights collide, hence they must have traveled for the same amount of time just before collision
From one of the equations of motion for linear motion
Where is the distance traveled
is the initial velocity
is the acceleration
and is the time
For Sir George,
= 0 m/s (Since they start from rest)
0.21 m/s²
Hence,
becomes
Now, for Sir Alfred
= 0 m/s (Since they start from rest)
0.26 m/s²
Hence,
becomes
Since, they traveled for the same time, just before collision, we can write
Since, the two nights are 86 m apart, that is, the sum of the distances covered by the knights just before collision is 86 m. Then we can write that
m
Then,
Then,
becomes
m
∴ Sir George covered a distance of 38.43 m just before collision.
Hence, relative to Sir George's starting point, the knights collide at a distance of 38.43 m from Sir George's starting point.