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MArishka [77]
3 years ago
6

The sun emits energy by converting hydrogen into helium. what is this process called?

Physics
1 answer:
AleksAgata [21]3 years ago
7 0
The answer is Nuclear Fusion. The sun emits energy by converting hydrogen into helium. Nuclear fusion does two things, it converts hydrogen into helium and it also converts mass to energy.
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Which statement describes the relationship between the rate of reaction and the temperature?
patriot [66]

PM me the statements, and i'll answer it then.

7 0
3 years ago
Determine the amount of torque
malfutka [58]

Answer:

250Nm

Explanation:

Given parameters:

Length of the long pry bar  = 1m

Force acting on it  = 250N

Angle  = 90°

Unknown:

Amount of torque applied  = ?

Solution:

Torque is the turning force on a body that causes the rotation of the body.

The formula is given as:

 Torque  = Force x r Sin Ф  

r is the distance

 So;

   Torque  = 250 x 1 x sin 90  = 250Nm

7 0
3 years ago
By how many times will the kinetic energy of a body increase if its speed is tripled? Show by calculation .​
alina1380 [7]

Answer:

9 lần

Explanation:

8 0
3 years ago
A 2498 kg car is moving at 17.1 m/s slams on its brakes and slows to 2.6 m/s. What is the magnitude (absolute value) of the impu
bija089 [108]

Answer:

<em>J=36221 Kg.m/s</em>

Explanation:

<u>Impulse-Momentum Theorem</u>

These two magnitudes are related in the following way. Suppose an object is moving at a certain speed v_1 and changes it to v_2. The impulse is numerically equivalent to the change of linear momentum. Let's recall the momentum is given by

p=mv

The initial and final momentums are, respectively

p_1=mv_1,\ p_2=mv_2

The change of momentum is

\Delta p=p_2-p_1=m(v_2-v_1)

It is numerically equal to the Impulse J

J=\Delta p

J=m(v_2-v_1)

We are given

m=2498\ kg,\ v_1=17.1\ m/s,\ v_2=2.6\ m/s

The impulse the car experiences during that time is

J=2498(2.6-17.1)=2498(-14.5)

J=-36221 Kg.m/s

The magnitude of J is

J=36221 Kg.m/s

8 0
3 years ago
A small plastic bead has been charged to -15nC.
marishachu [46]

Answer:

Explanation:

q = - 15 n C = - 15 x 10^-9 c

(a) d = 0.9 cm = 0.009 m

electric field on proton, E = Kq/d²

E = 9 x 10^9 x 15 x 10^-9 / (0.009)²

E = 1.67 x 10^6 N/C

Force on proton, F = charge on proton x Electric field

F = 1.6 x 10^-19 x 1.67 x 10^6 = 2.67 x 10^-13 N

acceleration of proton, a = F / m

a = (2.67 x 10^-13) / (1.67 x 10^-27)

a = 1.6 x 10^14 m/s²

(B) the direction of acceleration is towards the bead, as the force is attractive.

(C) d = 0.9 cm = 0.009 m

electric field on proton, E = Kq/d²

E = 9 x 10^9 x 15 x 10^-9 / (0.009)²

E = 1.67 x 10^6 N/C

Force on electron, F = charge on electron x Electric field

F = 1.6 x 10^-19 x 1.67 x 10^6 = 2.67 x 10^-13 N

acceleration of proton, a = F / m

a = (2.67 x 10^-13) / (9.1 x 10^-31)

a = 3 x 10^17 m/s²

(D) the direction of acceleration is away from the bead, as the force is repulsive.  

8 0
3 years ago
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