A trapezoid does not have 2 pair of parallel sides so we can cross that out. A rhombus does not have right angles so cross that out. So we got A and C. A square has 2 pair of parallel lines and and 4 right angle. Your answers should be.
<span>C. Square
It could not be A. Most likely its C. So you can pick both or just C.</span>
Answer:
13 and -14 satisfy this condition
Step-by-step explanation:
Let's represent that number as x
and the square of x is x^2
So,
x + x^2 = 182
Subtract 182 from both sides
x + x^2 - 182 = 182 - 182
x + x^2 - 182 = 0
rearrange the quadratic equation
x^2 + x -182 = 0
let's use the quadratic formula
or 
a = 1, b = 1, c = -182
or 
or 
or 
or 
or 
13 or - 14
Lets check
13 + 13^2 = 13 + 169
= 182
Also,
-14 + (-14^2) = -14 + 196
= 182
Answer: i think it’s no real solutions
Step-by-step explanation:
Answer:
x = - 
Step-by-step explanation:
Given
x + 2 = 
Multiply through by 24 ( the LCM of 6 and 8 ) to clear the fractions
20x + 48 = 21 ( subtract 48 from both sides )
20x = - 27 ( divide both sides by 20 )
x = - 