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3 years ago

How do the Earth and Moon compare in terms of gravitational force?

2 answers:

8 0

C. Earth's gravitational force is stronger than the Moon's.

Since Earth has a far larger mass than the Moon, its gravitational force is also higher.

ankoles [38]3 years ago

5 0

C. Earth's gravitational force is stronger than the Moon's.

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You have been given two samples of water. One is from the atlantic ocean and the other is from lake superior. Describe how you w

lbvjy [14]

Answer:

i think by their salinity (the saltiness or amount of salt dissolved in a body of water)

Explanation:

Water salinity is measured by passing an electric current between the two electrodes of a salinity meter in a sample of water.

5 0

2 years ago

Why is reactivity not a physical property

lbvjy [14]

Reactivity is not a physical property because it's a characteristic of a chemical element or compound and is involved in chemical process.

3 0

3 years ago

Some chemical factories make hydrogen gas (H2) using a process called steam methane reforming. In this process, methane (CH4) co

erica [24]

Answer:

steam and methane

Explanation:

5 0

2 years ago

Calculate the freezing point (in degrees C) of a solution made by dissolving 7.99 g of anthracene{C14H10} in 79 g of benzene. Th

mario62 [17]

<u>Answer:</u> The freezing point of solution is 2.6°C

<u>Explanation:</u>

To calculate the depression in freezing point, we use the equation:

$\Delta T_f=iK_fm$

Or,

$\Delta T_f=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}$

where,

$\Delta T_f$ = $\text{Freezing point of pure solution}-\text{Freezing point of solution}$

Freezing point of pure solution = 5.5°C

i = Vant hoff factor = 1 (For non-electrolytes)

$K_f$ = molal freezing point depression constant = 5.12 K/m = 5.12 °C/m

$m_{solute}$ = Given mass of solute (anthracene) = 7.99 g

$M_{solute}$ = Molar mass of solute (anthracene) = 178.23 g/mol

$W_{solvent}$ = Mass of solvent (benzene) = 79 g

Putting values in above equation, we get:

$5.5-\text{Freezing point of solution}=1\times 5.12^oC/m\times \frac{7.99\times 1000}{178.23g/mol\times 79}\\\\\text{Freezing point of solution}=2.6^oC$

Hence, the freezing point of solution is 2.6°C

8 0

2 years ago

What’s the answer for #9

zheka24 [161]

Freezer and refrigerator--> Too cold for most bacteria to grow (reproduce). Oven --> too hot for bacteria to survive

4 0

2 years ago