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laila [671]
4 years ago
8

In this problem, you will apply kinematic equations to a jumping flea. Take the magnitude of free-fall acceleration to be 9.80m/

s2 . Ignore air resistance.
A flea jumps straight up to a maximum height of 0.460m . What is its initial velocity v0 as it leaves the ground?
Physics
1 answer:
polet [3.4K]4 years ago
8 0
V o - initial velocity
v = velocity at the maximum height,
v² = v o² - 2 g h
v = 0
0 = v o² - 2 g h
v o² = 2 g h = 2 · 9.80 · 0.460
v o² = 9.052
v o = √9.052 = 3.004197 m/s ≈ 3 m/s
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dem82 [27]

The mechanical advantage of the lever is 3 and the right option is A.) 3.

<h3>What is mechanical advantage?</h3>

Mechanical advantage can be defined as the ratio of load to effort in a machine.

To calculate the mechanical advantage of the lever, we use the formula below.

Formula

  • M.A = y/x................ Equation 1

Where:

  • M.A = mechanical advantage of the lever
  • y = distance moved by effort (input arm)
  • x = distance moved by load (output arm)

From the question,

Given:

  • y = 3 m
  • x = 1 m

Substitute these values into equation 1

  • M.A = 3/1
  • M.A = 3.

Hence, The mechanical advantage of the lever is 3 and the right option is A.) 3.

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The force between two charges and the distance separating them.

Explanation:

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Starting from rest, a 75.0-kg snowboarder slides straight down a 115-m slope in 6.6 s. If the slope is a 35°
Likurg_2 [28]

The acceleration of the snowboarder is 5.6 m/s^2 down along the incline

Explanation:

To find the acceleration of the snowboard, we have to analyze the forces acting along the direction parallel to the incline.

There is only one force acting in this direction, and it is the component of the weight parallel to the incline, given by

mg sin \theta

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m = 75.0 kg is the mass of the man

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\theta=35^{\circ} is the angle of the incline

Substituting, we find that the net force along the incline is:

F=(75.0)(9.8)(sin 35^{\circ})=421.6 N

According to Newton's second law, the net force on the snowboard is equal to the product between his mass and his acceleration:

F=ma

where a is the acceleration. Therefore, solving for a, we find

a=\frac{F}{m}=\frac{421.6}{75}=5.6 m/s^2

And the direction of this acceleration is down along the incline.

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