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inysia [295]
2 years ago
14

What is the velocity of a car with a momentum of 100 kg*m/s and a mass of 35kg?

Physics
1 answer:
LuckyWell [14K]2 years ago
4 0

Answer:

<h2>2.86 m/s</h2>

Explanation:

The velocity of the car can be found by using the formula

v =  \frac{p}{m}  \\

p is the momentum

m is the mass

From the question we have

v =  \frac{100}{35}  =  \frac{50}{7}  \\  = 2.857142...

We have the final answer as

<h3>2.86 m/s</h3>

Hope this helps you

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Which will increase the kinetic energy of an object more, increasing its mass or increasing its speed? Why?
agasfer [191]
Increasing its velocity will add to the kinetic energy more as the formula for kinetic energy is 0.5*m*v^2. (The speed will be squared making it greater)
4 0
3 years ago
Does this graph represent constant or changing speed? How do you know? Find the average speed
stepan [7]
Constant speed because the time is directly proportional to the speed (2). The average speed is 2 m/s
6 0
2 years ago
What is the expected wavelength (in cm) of 10.5 ghz microwaves in free space?
Sindrei [870]

Wavelength = (speed) / (frequency)

Wavelength = (300 thousand km per second) / (10.5 billion per second)

Wavelength = (300 / 10.5) (thousand km per second) / (billion per second)

Wavelength = (28.57) (million meters / second) / (thousand million / second)

Wavelength = (28.57) (meters / second) / (thousand / second)

Wavelength = (28.57) (meters / thousand)

<em>Wavelength = (28.57) (millimeters) </em>

5 0
3 years ago
A comet fragment of mass 1.96 × 1013 kg is moving at 6.50 × 104 m/s when it crashes into Callisto, a moon of Jupiter. The mass o
vredina [299]

Answer:

Recoil speed, 1.17\times 10^{-5}\ m/s                          

Explanation:

Given that,

Mass of the comet fragment, m_1=1.96\times 10^{13}\ kg

Speed of the comet fragment, v_1=6.5\times 10^4\ m/s

Mass of Callisto, m_2=1.08\times 10^{23}\ kg

The collision is completely inelastic. Assuming for this calculation that Callisto's initial momentum is zero. So,

m_1v_1=(m_2+m_2)V

V is recoil speed of Callisto immediately after the collision.

V=\dfrac{m_1v_1}{(m_2+m_2)}\\\\V=\dfrac{1.96\times 10^{13}\times 6.5\times 10^4}{(1.96\times 10^{13}+1.08\times 10^{23})}\\\\V=1.17\times 10^{-5}\ m/s

So, the recoil speed of Callisto immediately after the collision is 1.17\times 10^{-5}\ m/s

7 0
3 years ago
A 54 kg man holding a 0.65 kg ball stands on a frozen pond next to a wall. He throws the ball at the wall with a speed of 12.1 m
Inessa [10]

Answer:

The velocity of the man is 0.144 m/s

Explanation:

This is a case of conservation of momentum.

The momentum of the moving ball before it was caught must equal the momentum of the man and the ball after he catches the ball.

Mass of ball = 0.65 kg

Mass of the man = 54 kg

Velocity of the ball = 12.1 m/s

Before collision, momentum of the ball = mass x velocity

= 0.65 x 12.1 = 7.865 kg-m/s

After collision the momentum of the man and ball system is

(0.65 + 54)Vf = 54.65Vf

Where Vf is their final common velocity.

Equating the initial and final momentum,

7.865 = 54.65Vf

Vf = 7.865/54.65 = 0.144 m/s

4 0
2 years ago
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