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ratelena [41]
3 years ago
11

El salto con garrocha es practicado por:

Physics
1 answer:
Ulleksa [173]3 years ago
8 0
D. Solo a y b
De nada
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A car travels at 15 m/s for 30 minutes. How far did it travel?
Brilliant_brown [7]

Answer:

27000 meters

Explanation:

15 x 60 x 30

5 0
3 years ago
A billiard ball with a mass of 1.5kg is moving at 25m/s and strikes a second ball with a mass of 2.3 kg that is motionless. Find
aliya0001 [1]

Answer:

The velocity of the second ball after the collision will be 16.3 m/s.

Step-by-Step Explanation:

Law of conservation of momentum states that the total momentum of an isolated remains the same before and after the collision.

Let: mass of the first ball = m1 = 1.5 kg

mass of the second ball = m2 =  2.3 kg

Momentum before the collision:

velocity of the first ball = v1 = 25 m/s

velocity of the second ball = v2 = 0 m/s

[tex] Initial momentum = m1v1 + m2v2 = 1.5*25 + 2.3*0 = 37.5 kgm/s [\tex]

Momentum after the collision:

velocity of the first ball = v1 = 0 m/s

velocity of the second ball = v2 = x

[tex]momentum after the collision= m1v1 + m2v2 = 1.5*0 + 2.3*x = 2.3*x[\tex]

According to law of conservation of momentum:

Initial momentum = Momentum after collision

37.5 = 2.3*x

⇒ x = 37.5/2.3

x = 16.3 m/s

4 0
3 years ago
Examine the cross-sectional slice of a stem of a mint plant. Which statement most specifically describes mint?
Maslowich

The available options are:

Mint is a dicot.

Mint is a monocot.

Mint is an angiosperm.

Mint is a bulb plant.

Answer:

Mint is a dicot.

Explanation:

Given the fact that Mint is considered to be a member of Lamiaceae, an angiosperm plant which is characterized by typically having leaves that consist of reticulate vacation and appears like veins in structure. It also has a seed that contains two cotyledons.

Hence, it is considered a DICOT PLANT due to these characteristics. The botanical name of Mint is referred to as Mentha arvensis.

7 0
3 years ago
A sled is accelerating down a hill at a rate of 1 m s2 . If the mass of the sled is suddenly cut in half and the net force on th
mihalych1998 [28]
We have that F=ma from the 2nd Newton law where F is the force, m is the mass and a is the acceleration. Suppose we have that F' is the new force and m' is the new mass. Then, we have that a'=F'/m' still, by rearranging Newton's law. We are given that F'=2F and m'=m/2. Hence,
a'= \frac{2F}{ \frac{m}{2} } = \frac{4F}{m} = 4\frac{F}{m}
But now, we have from F=ma, that a=F/m and we are given that a=1m/s^2.
We can substitute thus, a'=4a=4*1m/s^2=4m/s^2.
4 0
3 years ago
A ball of mass 0.10 kg moving at a speed of 3.0 m/s collides with a wall and bounces directly back with the same speed. If the b
alexdok [17]

The magnitude of the average force exerted on the ball by the wall is calculated below.

The average force exerted by the ball on the wall is 3 N

Explanation:

Given:

mass of the ball (m)=0.10 kg

speed (v) =3.0 m/s

time taken(t) =0.01 seconds

To calculate:

Average force(F) exerted by ball on the wall

We know;

F=(m×v)÷t

F=(0.10×3.0)÷0.01

<u><em>F=3 N</em></u>

Therefore the average force exerted by the ball on the wall is 3 N

8 0
4 years ago
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