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ratelena [41]
3 years ago
11

El salto con garrocha es practicado por:

Physics
1 answer:
Ulleksa [173]3 years ago
8 0
D. Solo a y b
De nada
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Sound waves can be modeled by the equation of the form y=20sin(3t+theta). Determine what type of interference results when sound
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In two or more complete sentences, explain how you can prove that the number of degrees that the Moon rotates around the Earth e
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Follows are the explanation to this question:

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A simple pendulum is used to measure gravity using the following theoretical equation,TT=2ππ�LL/gg ,where L is the length of the
Elina [12.6K]

Answer:

g ±Δg = (9.8 ± 0.2) m / s²

Explanation:

For the calculation of the acceleration of gravity they indicate the equation of the simple pendulum to use

          T = 2\pi  \sqrt{ \frac{L}{g} }

          T² =  4\pi ^2 \frac{L}{g}4pi2 L / g

          g = 4\pi ^2   \frac{L}{T^2}

They indicate the average time of 20 measurements 1,823 s, each with an oscillation

let's calculate the magnitude

           g = 4\pi ^2  \frac{0.823}{1.823^2}4 pi2 0.823 / 1.823 2

            g = 9.7766 m / s²

now let's look for the uncertainty of gravity, as it was obtained from an equation we can use the following error propagation

for the period

             T = t / n

             ΔT = \frac{dT}{dt} Δt + \frac{dT}{dn} ΔDn

In general, the number of oscillations is small, so we can assume that there are no errors, in this case the number of oscillations of n = 1, consequently

              ΔT = Δt / n

              ΔT = Δt

now let's look for the uncertainty of g

             Δg = \frac{dg}{dL} ΔL + \frac{dg}{dT}  ΔT

             Δg = 4\pi ^2 \frac{1}{T2}   ΔL + 4π²L  (-2  T⁻³) ΔT

           

a more manageable way is with the relative error

             \frac{\Delta g}{g}   = \frac{\Delta L }{L} + \frac{1}{2}  \frac{\Delta T}{T}

we substitute

              Δg = g ( \frac{\Delta L }{L} + \frac{1}{2}  \frac{\Delta T}{T}DL / L + ½ Dt / T)

the error in time give us the stanndard deviation  

let's calculate

               Δg = 9.7766 (\frac{0.001}{0.823} + \frac{1}{2}  \ \frac{0.671}{1.823})

               Δg = 9.7766 (0.001215 + 0.0184)

               Δg = 0.19 m / s²

the absolute uncertainty must be true to a significant figure

                Δg = 0.2 m / s2

therefore the correct result is

               g ±Δg = (9.8 ± 0.2) m / s²

5 0
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Net force is the vector sum of forces acting on a particle or body. The net force is a single force that replaces the effect of the original forces on the particle's motion. It gives the particle the same acceleration as all those actual forces together as described by the Newton's second law of motion.
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