An increase in motion and less attraction between particles
Mass of KCl= 19.57 g
<h3>Further explanation</h3>
Given
12.6 g of Oxygen
Required
mass of KCl
Solution
Reaction
2KClO3 ⇒ 2KCl + 3O2
mol O2 :
= mass : MW
= 12.6 : 32 g/mol
= 0.39375
From the equation, mol KCl :
= 2/3 x mol O2
= 2/3 x 0.39375
=0.2625
Mass KCl :
= mol x MW
= 0.2625 x 74,5513 g/mol
= 19.57 g
It contains nutrients and minerals that could sustain biological life
Answer:
Mass = 9.58 g
Explanation:
Given data:
Mass of Zn = 2g
Theoretical yield of ZnI₂ = ?
Solution:
Chemical equation:
Zn + I₂ → ZnI₂
Number of moles of Zn:
Number of moles = mass/molar mass
Number of moles = 2g / 65.38 g/mol
Number of moles = 0.03 mol
Now we will compare the moles of Zn and ZnI₂.
Zn : ZnI₂
1 : 1
0.03 : 0.03
Mass of ZnI₂:
Mass = number of moles × molar mass
Mass = 0.03 mol × 319.22 g/mol
Mass = 9.58 g
Answer:
Explanation:
Given that:-
Pressure = 
The expression for the conversion of pressure in Pascal to pressure in atm is shown below:
P (Pa) = 
P (atm)
Given the value of pressure = 43,836 Pa
So,
= 
atm
Pressure = 6.80977 atm
Volume = 
= 2.3 L ( 1 m³ = 1000 L)
n = 2 mol
Using ideal gas equation as:
PV=nRT
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L.atm/K.mol
Applying the equation as:
6.80977 atm × 2.3 L = 2 mol × 0.0821 L.atm/K.mol × T
⇒T = 95.39 K
The expression for the kinetic energy is:-
k is Boltzmann's constant = 
T is the temperature
So, 
