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AnnyKZ [126]
3 years ago
6

Calculate the hydrogen-ion concentration (H+] for the aqueous solution in which [OH-1 is 1 x 10-12 mol/L.

Chemistry
2 answers:
Artemon [7]3 years ago
7 0

Answer:If we have [H+][OH-]= Kw = 1.0 x 10^-14

Then [H+]= Kw/ [OH-]= 1.0x 10^-14/ 1 x 10^-11 =1 x 10^-3 mol/L

And here is the solution - as you can see it is an acidic one :

pH = - log [H+]= - log 1 x 10^-3 = 3 < 7

Explanation:

Vlad1618 [11]3 years ago
5 0

Answer:

[H+] = 0.01mol/L

Explanation:

p[OH] = -log[OH-]

[OH-] = 1*10^-12

pOH = -Log[1*10^-12]

pOH = 12.

But pH + pOH = 14

pH = 14 - pOH

pH = 14 - 12

pH = 2

pH = -Log[H+]

2 = -Log[H+]

Take the anti log of both sides

10⁻² = [H+]

[H+] = 0.01

The hydrogen ion concentration is 0.01mol/L

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7 0
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Answer:

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Explanation:

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The given reaction is double displacement reaction in which anion and cation of both reactant exchanged with each other. Calcium hydroxide react with sulfuric acid and form calcium sulfate and water.

Double replacement:

It is the reaction in which two compound exchange their ions and form new compounds.

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6 0
3 years ago
When PCl5 solidifies it forms PCl4+ cations and PCl6– anions. According to valence bond theory, what hybrid orbitals are used by
Vlad1618 [11]

Answer:

sp³

Explanation:

Number of hybrid orbitals = ( V + S - C + A ) / 2

Where

H is the number of hybrid orbitals

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C is the number of cations = 1

A is the number of anions = 0

For PCl₄⁺

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H = ( 5+4-1+0) / 2

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5 0
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Read 2 more answers
Which metal will more easily lose an electron sodium or potassium?
sergey [27]
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eduard

0.0081599680129254

Hope this helps?

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