The correct answer is:
DNA template 3'– ……… –5'
RNA transcript 5'– ……… –3'
Protein product H2N– ……. –COOH
In nucleic acids, DNA and RNA 5’ end refers to phosphate group attached to the 5′ carbon of the ribose ring, while 3’ end refers to the ribose -OH substituent. Nucleic acids can only be synthesized in the 5′-to-3′ direction, which means that the DNA template is 3’—5’. Translation of the protein by the ribosome will also proceed in a 5′ to 3′ direction, which means that the mRNA template is 3’—5’.
The protein during the synthesis is extend from its N terminus toward its C terminus.
"Prokaryote" is shown in the given image.
Answer: Option A
<u>Explanation:</u>
A prokaryote is a single-cell organism which is deficient in a membranous nucleus, mitochondria, or any other membranous organs. Prokaryotes are categorized into two domains: Bacteria and Archaea. At the third domain: Eukaryota, species with nuclei and organelles are located.
The asexual prokaryotes reproduce without fusion of gametes. They are considered as first living organisms. In the prokaryotes components like proteins, DNA and metabolites, overall the intra-cellular water-soluble components are enclosed by the cell membrane as situated together in the cytoplasm, rather than in separate cellular compartments.
The short answer is that cells respond to the chemical environment in which they find themselves. The cells around them, the specific conditions, and feedback from the environment all create specific chemical cues that inform the cells to which genes should be expressed, and in what amounts. Chemicals include hormones, cytokines, general signaling molecules, such as cAMP, etc.
i literally hopped on google for this, lol.
i hope this helps though. :)
