Answer:
Option A:
Zn(s) + Cu^(2+) (aq) → Cu(s) + Zn^(2+)(aq)
Explanation:
The half reactions given are:
Zn(s) → Zn^(2+)(aq) + 2e^(-)
Cu^(2+) (aq) + 2e^(-) → Cu(s)
From the given half reactions, we can see that in the first one, Zn undergoes oxidation to produce Zn^(2+).
While in the second half reaction, Cu^(2+) is reduced to Cu.
Thus, for the overall reaction, we will add both half reactions to get;
Zn(s) + Cu^(2+) (aq) + 2e^(-) → Cu(s) + Zn^(2+)(aq) + 2e^(-)
2e^(-) will cancel out to give us;
Zn(s) + Cu^(2+) (aq) → Cu(s) + Zn^(2+)(aq)
C is incorrect n3- is the formula for nitride ion
Is correct hope this helps i have done this before
Answer:
This is and ADDITION REACTION
Explanation:
Because your putting a compound and an element together
The statement in option B is not correct. B is the correct answer. This is because nuclear fission usually occur in large unstable isotopes, which are bombarded with high speed particles like neutrons, which make them to split into smaller particles. The statement in option A, C and D are true about nuclear fission.