1. Strategy I would use
Let me show you an strategy:
<u>Break apart strategy:</u>
The strategy of break apart numbers (Place Value) consists in the decomposition or separation of numbers. We can break both numbers down to place value and add each, starting with the largest or keep one number intact and only break second number down by place value and adding each place. Anyway, using this strategy we have:
2 + 8 = ?
2 breaks into 1 plus 1 (1 + 1), 8 breaks into 4 plus 4 (4 + 4), so by associative property:
(1+4)+(1+4) = 5+5=10
2. Explain how I decided.
This strategy is good to add larger numbers. In this way, we may break larger numbers up into hundreds, tens, ones, then add. This is an easy way to find additions.
Naming the circle is just the only point in the center of the circle (E). The radius is half diameter of the circle so imagine a line connecting the center dot to any dot to the outside. An example of this would be (EC). The diameter is half the circle so any 3 points that cut the circle in half. This could be either (DEC) or (AEB).
So the answers would be:
A: (E)
B: (EC)
C: (DEC)
D: (AEB)
Answer:
x = -6 and x = 1
Step-by-step explanation:
Move everything to the left side of the equation by subtracting (-10x + 12)
2x² = -10x + 12
2x² + 10x - 12 = 0
Divide each side by 2:
x² + 5x - 6
Find 2 factors of -6 that add up to 5. These factors are 6 and -1
x² + 5x - 6
(x + 6)(x - 1)
Set this equal to 0 and solve for x
(x + 6)(x - 1)
x + 6 = 0
x = -6
x - 1 = 0
x = 1
So, the solutions to the equation are x = -6 and x = 1
The answer is 3f
<span>=<span><span>18f</span>+<span>−<span>15f</span></span></span></span><span>=<span>(<span><span>18f</span>+<span>−<span>15f</span></span></span>)</span></span><span>=<span>3<span>f</span></span></span>
Answer:
See below for answers and explanations
Step-by-step explanation:
I assume the function you wrote was
1) The equation for the horizontal asymptote is y=-2 since a function of the form f(x) = a(b^x) + c always has a horizontal asymptote at y = c, so c=-2, therefore the horizontal asymptote equation is y=-2
2) The range is (-∞,-2) since any real value of y that is less than -2 but doesn't equal -2 (since it's not included) will be a solution.
3) The domain is (-∞,∞) since any real value of x will be a solution.
4) The axis that f(x) is reflected over is the x-axis because when you negate a base in an exponential function, that will occur.