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aalyn [17]
3 years ago
13

Eight times the difference of a number and seventeen is thirty"?

Mathematics
1 answer:
ladessa [460]3 years ago
5 0
"The number" is first, do an example, to find out how, like pick any number under 17. Let's do 14. Their difference is 3. 8*3=24. that;s not quite 30. We have to find a number to equal 30, let's pick 15 and 17. Their difference is 2. 2*8=16. Not quite. Now, check the multiplication table for 8. Do any of them equal 30? No. So now you can see that the answer is going to have a decimal place. Divide 30 by 8. That equals to 3.75. Now do 17 minus 3.75. That is 13.25. The difference between 13.25 and 17 is 3.25. Now, do 8*3.75. That is 26. Oops. I am not in high school, but keep going like that and YOU'LL FIND IT! I BELIEVE IN YOU!
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What is the decimal of 64/100
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Divide the numerator by the denominator. hope this helps! :))

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4 years ago
Thirty percent of all customers who enter a department store will make a purchase. Suppose that 6 customers enter the store and
torisob [31]

Answer:

Step-by-step explanation:

Let's use binomial distribution, because we are interested in find the total number of successes in a sequence of n independent experiments.

In probability, a binomial distribution is used in a Bernoulli process. That is, a sequence of experiments of n independent  trials, each asking a dichotomous question, that means it only has two answers. One answer is a success (probability: p) and the other is a failure (probability: 1-p). In this case, every customer who enters in the store is the experiment. If they make a purchase is a success event, taking into account that every purchase decision has to be independent.

P(X=x) = C(n,x)p^{x} (1-p)^{n-x}

x= total number of success

n= total number of experiments

p=probability of success on an indivual trial

C(n,x) = \frac{n!}{x!(n-x)!}

a) x= 5 ------> customers that make a purchase

n= 6 ------> total customers

p=0.3

p(X=5)= C(6,5)(0.3)^{5} (1-0.3)^{6-5} \\p(X=5)=0.102

b) At least 3 customers make a purchase. x ≥ 3

P(X\geq 3)=1-P (X=0)-P(X=1)-P(X=2)\\P(X\geq 3)=1-(C(6,0)(0.3^{0})(0.7)^{6}) - (C(6,1)(0.3^{1})(0.7)^{5}) - (C(6,2)(0.3^{2})(0.7)^{4})\\ P(X\geq 3) = 1-0.11765-0.30253-0.32414\\P(X\geq3)= 0.2557

c) At most 2 customers make a purchase. x ≤ 2

P(X\leq2) = P(X=0) + P(X=1) + P(X=2)\\P(X\leq2) = (C(6,0)(0.3^{0})(0.7)^{6}) + (C(6,1)(0.3^{1})(0.7)^{5}) + (C(6,2)(0.3^{2})(0.7)^{4})\\P(X\leq2) = 0.11765-0.30253-0.32414\\P(X\leq2)=0.7443

d)At least 1 customer makes a purchase. x ≥ 1

P(X\geq 1)=1-P(X=0)\\P(X\geq 1)= 1-C(0,6)(0.3)^{0}(0.7)^{6} \\P(X\geq 1)= 1-0.11765 = 0.8824

e)They must be kind to customers, always willing to help and give information about products clearly and honestly.

Have enough inventory and offer promotions for the purchase of more than one product

Have an agile payment system that avoids rows and delays in purchases.

6 0
3 years ago
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