1.) What coefficient values will balance the reaction shown? CH4 + O2 ?CO2 + H2O

mamaluj [8]

The structure that corresponds to methylpropylether is the structure CH3 - O - C3H7 in option C.

<h3>What is structure?</h3>

The structure of a compound is defined as the way in which the atoms in the compound are arranged. We know that a compound is composed of atoms and these atoms are arranged in particular patterns in space. This is the stereochemistry of the molecule.

Now we know that methylpropylether is a compound that contains the methyl group and the propyl group separated by a oxygen atom as is typical of all ethers.

As such, the structure that corresponds to methylpropylether is the structure CH3 - O - C3H7 in option C.

Learn more about methylpropylether:brainly.com/question/28047849

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4 0

1 year ago

The solubility of silver(I)phosphate at a given temperature is 1.02 g/L. Calculate the Ksp at this temperature. After you get yo

Snezhnost [94]

Answer: The solubility product of silver (I) phosphate is $9.57\times 10^{-10}$

Explanation:

We are given:

Solubility of silver (I) phosphate = 1.02 g/L

To convert it into molar solubility, we divide the given solubility by the molar mass of silver (I) phosphate:

Molar mass of silver (I) phosphate = 418.6 g/mol

$\text{Molar solubility of silver (I) phosphate}=\frac{1.02g/L}{418.6g/mol}=2.44\times 10^{-3}mol/L$

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

The chemical equation for the ionization of silver (I) phosphate follows:

$Ag_3PO_4(aq.)\rightleftharpoons 3Ag^{+}(aq.)+PO_4^{3-}(aq.)$

3s s

The expression of $K_{sp}$ for above equation follows:

$K_{sp}=(3s)^3\times s$

We are given:

$s=2.44\times 10^{-3}M$

Putting values in above expression, we get:

$K_{sp}=(3\times 2.44\times 10^{-3})^3\times (2.44\times 10^{-3})\\\\K_{sp}=9.57\times 10^{-10}$

Hence, the solubility product of silver (I) phosphate is $9.57\times 10^{-10}$

4 0

2 years ago

The adult blue whale has a lung capacity 5.0\times10^3 5.0 Ã 10 3 l. calculate the mass of air (assume an average molar mass of

Andre45 [30]

For this item, we need to assume that air behaves like that of an ideal gas. Ideal gases follow the ideal gas law which can be written as follow,
PV = nRT
where P is the pressure,
V is the volume,
n is the number of mols,
R is the universal gas constant, and
T is temperature

In this item, we are to determine first the number of moles, n. We derive the equation,
n = PV /RT
Substitute the given values,

n = (1 atm)(5 x 10³ L) / (0.0821 L.atm/mol.K)(0 + 273.15)
n = 223.08 mols

From the given molar mass, we calculate for the mass of air.
m = (223.08 mols)(28.98 g/mol) = 6464.9 g

ANSWER: 6464.9 g

8 0

2 years ago

NOOOOO LIINNNKKKKSSSSSS RIGHT ANSWERS ONLY!!!!!!!!!!!!!!!!!!!!!!!!!!

natta225 [31]

Answer:

Explanation:

The answer is B because looking at a map, tundra is at 60 and 70 degrees north. Also, the tundra is cold, and the other answers are hot places.

7 0

2 years ago

Read 2 more answers

Answer 3 & 4

Anastasy [175]

Answer:

The answer for 2-hexene is that the structure should have 6 carbon with a double bond beginning on the 2nd carbon atom.

The answer for 1-pentyne is that the structure should have 5 carbon with triple bond beginning on the 1st carbon atom.

Explanation:

2-Hexene

The structural formula for 2-hexene will have 6 carbons because the nomenclature has a -hex prefix, which stands for 6 carbons.

The -ene suffix of the nomenclature means that the organic compound is an alkene. Alkenes are hydrocarbons that contain double covalent bond and have the suffix -ene.

The double bond is on the 2 carbon atom because the nomenclature states that the double bond will be on the 2 carbon atom.

1-Pentyne

The structure will have 5 carbons since the -pent prefix means 5 carbons.

The structure has a triple bond because the -yne suffix means that the structure is an alkyne. An alkyne is a hydrocarbon with triple covalent bonds.

Also, the position of the triple bond is known because the nomenclature of the alkyne states that the triple bond is on the 1st carbon.

5 0

2 years ago