1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Bad White [126]
2 years ago
12

A reactant and a product of nuclear fission. A. Neutron B. Gamma

Chemistry
1 answer:
Readme [11.4K]2 years ago
3 0

Answer:

Neutron

Explanation:

You might be interested in
During one researcher's experiment, the total mass of the gas-generating solid and entire assembly was 52.1487g before the react
irinina [24]

Answer:

43.93 g/mol

Explanation:

The mass of the gas before reaction = 52.1487 g

The mass of the gas after reaction = 52.1098 g

Mass of gas generated = 0.0389 g

Moles of the gas = 8.854\times 10^{-4}\ moles

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Molar\ mass = \frac{Mass\ taken}{Moles}

Molar\ mass= \frac{0.0389\ g}{8.854\times 10^{-4}\ moles}

Molar mass of the gas = 43.93 g/mol

7 0
3 years ago
Which one of the following represents the number of units of each substance
netineya [11]

Answer:B

Explanation:Coefficient represents the number of units of each substance.

4 0
3 years ago
A 0.216 g sample of carbon dioxide, CO2, has a volume of 507 mL and a pressure of 470 mmHg. What is the temperature of the gas i
Gala2k [10]

Answer:

The temperature of the gas is 876.69 Kelvin

Explanation:

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

P*V = n*R*T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.

In this case:

  • P= 470 mmHg
  • V= 570 mL= 0.570 L
  • n= 0.216 g= 0.0049 moles (being the molar mass of carbon dioxide is 44 g/mole)
  • R= 62.36367 \frac{mmHg*L}{mol*K}
  • T=?

Replacing:

470 mmHg*0.570 L= 0.0049 moles* 62.36367 \frac{mmHg*L}{mol*K} *T

Solving:

T=\frac{470 mmHg*0.570 L}{0.0049 moles* 62.36367\frac{mmHg*L}{mol*K} }

T= 876.69 K

<em><u>The temperature of the gas is 876.69 Kelvin</u></em>

6 0
3 years ago
Hii pls help me to balance the equation thanksss​
tiny-mole [99]

▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓

\boxed{\pmb{\color{gold}{\sf{2SO_{2}(g) + O_{2}(g)\dashrightarrow 2SO_{3}(g)}}}}

▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓

7 0
3 years ago
Read 2 more answers
2. Calculate the density of a metal that occupies 17.75 cm and has a mass of 342.93 g. [D = m/V]
satela [25.4K]

Answer:

19.32

Explanation:

the density is given by the mass over volume

the mass In this case is 342.93 and the volume is 17.75

d=342.93g/17.75cm

=19.32g/cm

i hope this helps

3 0
3 years ago
Other questions:
  • Which of the following is a description of an exothermic reaction?
    10·1 answer
  • What Is Oxidation Reaction
    6·1 answer
  • Consider an atom that has an electron in an excited state. The electron falls to a lower energy level. What effect does that hav
    12·1 answer
  • Why must you be cautious of chemical exposure in the workplace?
    9·1 answer
  • If a bar of motilium cost .0.2 dollars how much will 200 bars cost
    7·1 answer
  • Which substance can not be broken down by a chemical change?
    10·1 answer
  • Explain how how radioactive decay can result in one element changing into another?
    14·1 answer
  • Which substances are released during cellular respiration?
    10·1 answer
  • If I dilute 334.75 mL of 1.28 M lithium acetate solution to a volume of 822.18 ml, what
    9·1 answer
  • 3 key features of Asteroid
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!