Answer:
Tom walked until he was 100 metres from his home. Then, he realised that he had dropped his homework, so he turned around and went 60 metres to pick it up again. He again turned back and started to walk faster to get to the bus stop on time. He got to the bus stop 100 seconds after leaving his home and waited for the bus.
Explanation:
Answer:
b. The rate at which charge flows
Explanation:
First we must complete the question:
Which of the following describes the measure of current:
a. The quality of the charge flow
b.The rate at which charge flows
c. The ability for something to have a charge flow
d.The potential for a charge to flow
The answer is b) The rate at which charge flows
The electric current is the electric charge flow that passes through a conductive material for a certain period of time. It is expressed in C / s, culombios per second in the international system of units, and the unit is known as Ampere (a)
The charge can be defined by culombio [C]
Answer:
3. you need to ask your available lab instructors what to do.
4. You immediately have to drop down your cloth and roll it to extinguish the fire or move to the emergency shower if available
5. You have too keep calm and report to the lab instructor but do no shout.
6. Move immediately to the eye rinse basin if available and wash your eyes gently and thoroughly
if the distance between the objects is doubled the force is reduced by a factor of 4
<h3>Whats is gravitational force?</h3>
Gravitational force is the force of attraction between objects in the universe.
f = G * m1 * m2 / r^2
f = gravitational force
G = gravitational constant
m1 = mass of object 1
m2 = mass of object 2
r = distance between the objects
From the formular, the gravitational force and the distance is an inverse relationship so increasing the distance by a factor results to reduction of the force by the square of the factor. hence doubling the distance which is distance mutiplied by 2 will lead to reduction of the force by 2^2 = 4
Therefore: The force decreases by a factor of 4.
hope it helps
Answer:

Explanation:
Given data:
v = 220 rms
power factor = 0.65
P = 1250 W
New power factor is 0.9 lag
we knwo that

s = 1923.09 < 49.65^o
s = [1250 + 1461 j] vA
![P.F new = cos [tan^{-1} \frac{Q_{new}}{P}]](https://tex.z-dn.net/?f=P.F%20new%20%3D%20cos%20%5Btan%5E%7B-1%7D%20%5Cfrac%7BQ_%7Bnew%7D%7D%7BP%7D%5D)
solving for 
![Q_{new} = P tan [cos^{-1} P.F new]](https://tex.z-dn.net/?f=Q_%7Bnew%7D%20%3D%20P%20tan%20%5Bcos%5E%7B-1%7D%20P.F%20new%5D)
![Q_{new} = 1250 [tan[cos^{-1}0.9]]](https://tex.z-dn.net/?f=Q_%7Bnew%7D%20%3D%201250%20%5Btan%5Bcos%5E%7B-1%7D0.9%5D%5D)






Faraday
