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Paladinen [302]

3 years ago

9

The equation for the speed of a satellite in a circular orbit around the earth depends on mass. Which mass?

1 answer:

katovenus [111]3 years ago

6 0

<h3><u>Question: </u></h3>

The equation for the speed of a satellite in a circular orbit around the Earth depends on mass. Which mass?

a. The mass of the sun

b. The mass of the satellite

c. The mass of the Earth

<h3><u>Answer:</u></h3>

The equation for the speed of a satellite orbiting in a circular path around the earth depends upon the mass of Earth.

Option c

<h3><u> Explanation: </u></h3>

Any particular body performing circular motion has a centripetal force in picture. In this case of a satellite revolving in a circular orbit around the earth, the necessary centripetal force is provided by the gravitational force between the satellite and earth. Hence $F_{G} = F_{C}$ .

Gravitational force between Earth and Satellite: $F_{G} = \frac{G \times M_e \times M_s}{R^2}$

Centripetal force of Satellite : $F_C = \frac{M_s \times V^2}{R}$

Where G = Gravitational Constant

$M_e$ = Mass of Earth

$M_s$ = Mass of satellite

R= Radius of satellite’s circular orbit

V = Speed of satellite

Equating $F_G = F_C$ , we get

Speed of Satellite $V =\frac{\sqrt{G \times M_e}}{R}$

Thus the speed of satellite depends only on the mass of Earth.

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krok68 [10]

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6 0

2 years ago

Read 2 more answers

assume the suns total energy output is 4.0 * 10^26 watts, and 1 watt is 1 joule/second. assume 4.3 * 10^-12 J is released from e

Dmitry [639]

Answer:

$9.3\cdot 10^{37}$

Explanation:

Power is defined as the energy produced (E) per unit of time (t):

$P= \frac{E}{t}$

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$E=Pt=(4.0\cdot 10^{26}W)(1s )=4.0\cdot 10^{26} J$

Each p-p chain reaction produces an amount of energy of

$E_1 = 4.3\cdot 10^{-12} J$

in order to get the total number of p-p chain reactions per second, we need to divide the total energy produced per second by the energy produced by each reaction:

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3 years ago

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Alenkasestr [34]

Answer:

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3 0

2 years ago

The figure shows five electric charges. Four charges with the magnitude of the charge 2.0 nC form a square with the size a = 4.0

bearhunter [10]

Considering the four electric charges forming a square with magnitude of charge of 2.0 nC on each. :

A) Magnitude of the force on the 5.5 nC charge in the middle of the figure = 3.48 * 10^-4 N

B) Direction of the force on the 5.5 nC charge in the middle of the figure = Leftward ( negative x -axis )

Using the given data :

size of square = 4 cm

magnitudes of four charges = 2.0 nC

<u> a) </u><u>magnitude</u><u> of the force on the center charge </u>

Electric force between two point charges = $F = \frac{1}{4\pi *E_{o} } \frac{q1q2}{r^2}$ ----- ( 1 )

where ; $\frac{1}{4\pi E_{o} } = 9 * 10^9 Nm^2/C^2$

step 1 ; find r ( distance between charges )

r² = ( 2 )² + ( 2 )² = 8 cm²

back to equation 1

F = 9 * 10⁹ * $\frac{2 * 10^{-9} * (5.5 * 10^{-9}) }{8*10^{-4} }$ = 1.23 * 10^-4 N

∴ magnitude of the force on the center charge ( Fnet )= 4F cos 45°

= 4 * ( 1.23 * 10^-4 ) * $\frac{1}{\sqrt{2} }$ = 3.48 * 10^-4 N

b) The direction of the force at the center is along the negative x-axis ( leftward )

Learn more : brainly.com/question/24139734

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2 years ago