Question

Stuntman's Freefall, a ride at Six Flags Great Adventure in New Jersey, stands 39.6 meters high. Ignoring the force of friction, what is the minimum power rating of the motor that raises the 1.20×105 kg ride from the ground to the top in 10.0 seconds at a constant velocity?

Answer 1

Answer:

Power, $P=4.65\times 10^6\ watts$

Explanation:

It is given that,

Mass, $m=1.2\times 10^5\ kg$

Height of the free fall, h = 39.6 m

Time taken, t = 10 s

Let P is the power rating of the motor. The energy per unit time is called power delivered to an object. Its formula is given by :

$P=\dfrac{W}{t}$

$P=\dfrac{mgh}{t}$

$P=\dfrac{1.2\times 10^5\ kg\times 9.8\ m/s^2\times 39.6\ m}{10\ s}$

P = 4656960 Watts

$P=4.65\times 10^6\ watts$

So, the power rating of the motor is $4.65\times 10^6\ watts$. Hence, this is the required solution.