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Vlad [161]
3 years ago
10

Stuntman's Freefall, a ride at Six Flags Great Adventure in New Jersey, stands 39.6 meters high. Ignoring the force of friction,

what is the minimum power rating of the motor that raises the 1.20×105 kg ride from the ground to the top in 10.0 seconds at a constant velocity?
Physics
1 answer:
Artyom0805 [142]3 years ago
4 0

Answer:

Power, P=4.65\times 10^6\ watts

Explanation:

It is given that,

Mass, m=1.2\times 10^5\ kg

Height of the free fall, h = 39.6 m

Time taken, t = 10 s

Let P is the power rating of the motor. The energy per unit time is called power delivered to an object. Its formula is given by :

P=\dfrac{W}{t}

P=\dfrac{mgh}{t}

P=\dfrac{1.2\times 10^5\ kg\times 9.8\ m/s^2\times 39.6\ m}{10\ s}

P = 4656960 Watts

P=4.65\times 10^6\ watts

So, the power rating of the motor is 4.65\times 10^6\ watts. Hence, this is the required solution.

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Answer:

D. 3 hours or more

Explanation:

The average 8- to 18-year-old spends at least D. 3 hours every day in front of a screen, performing little to no physical activity. This is because, instead of exercising and socializing with their peers, children and teenagers frequently talk, watch a lot of movies/shows, or play video games on their computers. Unfortunately, this is typically considerably more than three hours every day. Although some children still prefer physical activities over this, the bulk of the population does not.

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From the top of the engineering building, you throw a ball vertically upward. the ball strikes the ground 4.00 s later. the engi
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Equations of the vertical launch:

Vf = Vo - gt

y = yo + Vo*t - gt^2 / 2

Here yo = 35.0m
Vo is unknown
y final = 0
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and I will approximate g to 10m/s^2

=> 0 = 35.0 + Vo * 4 - 5 * (4.00)^2 => Vo = [-35 + 5*16] / 4 = - 45 / 4 = -11.25 m/s

The negative sign is due to the fact that the initial velocity is upwards and we assumed that the direction downwards was positive when used g = 10m/s^2.

Answer: 11.25 m/s


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3 years ago
Read 2 more answers
Calculate the pressure exerted by a 4000N camel on the sand. The camel’s feet have a
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Answer:

The pressure exerted by camel feet is <u>2000 N/m²</u>.

Step-by-step explanation:

<h3><u>Solution</u> :</h3>

Here, we have given that ;

  • Force applied on camel feet = 4000 N
  • Total area of camel feet = 2 m²

We need to find the pressure exerted by camel feet.

As we know that :

{\longrightarrow{\pmb{\sf{Pressure= \dfrac{Area}{Force}}}}}

Substituting all the given values in the formula to find the pressure exerted by camel feet.

\begin{gathered} \begin{array}{l} {\longrightarrow{\sf{Pressure= \dfrac{Area}{Force}}}} \\  \\ {\longrightarrow{\sf{Pressure= \dfrac{4000}{2}}}}  \\  \\ {\longrightarrow{\sf{Pressure= \cancel{\dfrac{4000}{2}}}}} \\  \\ {\longrightarrow{\sf{Pressure= 2000 \: N/{m}^{2}}}} \\  \\\star \:  \small\underline{\boxed{\sf{\purple{Pressure= 2000 \: N/{m}^{2}}}}} \end{array}\end{gathered}

Hence, the pressure exerted by camel feet is 2000 N/m².

\rule{300}{2.5}

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